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An unbiased die is thrown and B is an event showing an odd number on top. Then \(P(B)\)

  • A.\(\frac{1}{4}\)
  • B.\(\frac{1}{3}\)
  • C.\(\frac{1}{6}\)
  • D.\(\frac{1}{2}\)
  • E.\(\frac{1}{5}\)

Answer: D

The probability is \(\frac{1}{2}\).

A fair die has six equally likely faces, of which three, 1, 3 and 5, are odd.

\[ P(B) = \frac{3}{6} = \frac{1}{2} \]

\(\frac{1}{6}\) is the probability of one particular face, \(\frac{1}{3}\) of two faces, and \(\frac{1}{4}\) and \(\frac{1}{5}\) do not correspond to any count of the six faces.

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