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Critical thickness of insulation (rcr) for a pipe having thermal conductivity (k) and convective heat transfer coefficient (ho) is __________.

  • A.\(2k/h_{o}\)
  • B.\(k/h_{o}\)
  • C.\(h_{o}/k\)
  • D.\(2h_{o}/k\)

Answer: B

The critical radius of insulation for a pipe is \(k/h_{o}\).

For insulation of outer radius r on a pipe, the total resistance per unit length is conduction through the insulation plus convection from its outer surface:

\[ R' = \frac{\ln(r/r_{i})}{2\pi k} + \frac{1}{2\pi r h_{o}} \]

Setting \(dR'/dr = 0\) gives \(\frac{1}{kr} = \frac{1}{h_{o}r^{2}}\), so \(r_{cr} = k/h_{o}\). Below this radius, adding insulation actually increases heat loss, because the larger surface gains more convection than the extra conduction resistance costs.

\(2k/h_{o}\) is the critical radius for a sphere. \(h_{o}/k\) and \(2h_{o}/k\) invert the ratio and do not even have the units of length.

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