Machine-translated by Google. Questions are authored in English.
Top

Discussion

Absolute configuration of the chiral centres (C-2, C-4) and prochirality descriptors (HA and HB) in the following compound is :

(Fischer projection, top to bottom:)

COOH
HC-2OH
HAC-3HB
HC-4OH
COOH

  • A.2R, 4S; \(\text{H}_{A}\) : Pro-s; \(\text{H}_{B}\) : Pro-r
  • B.2R, 4R; \(\text{H}_{A}\) : Pro-s; \(\text{H}_{B}\) : Pro-r
  • C.2S, 4S; \(\text{H}_{A}\) : Pro-r; \(\text{H}_{B}\) : Pro-s
  • D.2S, 4R; \(\text{H}_{A}\) : Pro-s; \(\text{H}_{B}\) : Pro-r

Answer: A

The descriptors are 2R, 4S; HA pro-s; HB pro-r.

C-2: priorities OH > COOH > C-3 > H. With H on a horizontal bond, OH (right) to COOH (top) to C-3 (bottom) runs anticlockwise, which reads S; because the lowest priority group points towards the viewer, the true descriptor is reversed: R.

C-4: priorities OH > COOH (bottom) > C-3 (top) > H. OH to COOH to C-3 runs clockwise, read as R and reversed to S. Both OH groups on the same side make this the meso (2R,4S) diacid.

HA: replace it by D. At C-3 the R branch ranks above the S branch, so C-2 > C-4 > D > HB. C-2 (top) to C-4 (bottom) to D (left) runs clockwise, read as r and reversed (HB is horizontal) to s. So HA is pro-s and HB pro-r, which only the first option gives with 2R, 4S.

No comment is present. Be the first to comment.
Loading…

Post your comment

Please log in or register to post a comment.