Discussion
An optically active compound among the following is
Answer: E
The optically active compound is 2-Chlorobutane.
A molecule is optically active when it is chiral, and the usual cause is a carbon atom carrying four different groups. In 2-chlorobutane, CH3CH(Cl)CH2CH3, carbon 2 bears H, Cl, CH3 and C2H5: four different groups, so the molecule exists as a pair of non-superimposable mirror images.
None of the others has such a carbon. 1-Chlorobutane has Cl on a CH2. Neopentyl chloride, (CH3)3CCH2Cl, and isobutyl chloride, (CH3)2CHCH2Cl, have carbons with two identical groups. tert-Butyl chloride, (CH3)3CCl, has three identical methyl groups on the carbon bearing chlorine.
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