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Given the IP address 201.14.78.65 and the subnet mask 255.255.255.224. What is the subnet address ?

  • A.201.14.78.32
  • B.201.14.78.64
  • C.201.14.78.65
  • D.201.14.78.224

Answer: B

The subnet address is 201.14.78.64. It is obtained by a bitwise AND of the address and the mask. Only the last octet is affected, since the first three octets of the mask are 255.

\[ 65 = 01000001_{2} \]

\[ 224 = 11100000_{2} \]

\[ 01000001 \wedge 11100000 = 01000000 = 64 \]

So the subnet address is 201.14.78.64. The value 201.14.78.32 would need a last octet in the range 32 to 63, and .65 and .224 are the host address and the mask, which are not the network address.

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