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Why does a mixer's conversion loss matter to the noise budget?

  • A.It widens the effective noise bandwidth of the following amplifier
  • B.It reduces the gain protecting later stages
  • C.It increases the local oscillator power the mixer requires
  • D.It shifts the intermediate frequency away from its nominal value

Answer: B

Loss in the mixer reduces the accumulated gain, so the intermediate frequency amplifier's own noise is divided by less and contributes more. Oscillator power is a drive requirement rather than a noise consequence. The intermediate frequency is set by the oscillator's offset and does not shift. And noise bandwidth is a filter property. Wherever a chain loses gain, everything after that point becomes more important to the noise figure, which is why a preamplifier usually precedes a passive mixer.

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