Discussion
The power developed by a cylindrical rotor synchronous motor varies with the torque angle as
Answer: D
Correct answer: \( \sin\delta \)
For a cylindrical rotor machine with negligible armature resistance,
\[ P = \frac{EV}{X_s}\sin\delta \]where \( E \) is the excitation emf, \( V \) the terminal voltage and \( X_s \) the synchronous reactance. The power therefore rises with \( \delta \) to a maximum at 90 degrees and falls thereafter. A salient pole machine adds a reluctance term in \( \sin 2\delta \), which shifts its maximum below 90 degrees, but the cylindrical rotor machine has only the fundamental term.
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