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If the load on a synchronous motor is increased beyond its pull-out value, the machine will

  • A.slow down smoothly and continue to carry the load at reduced speed
  • B.increase its excitation automatically to carry the extra load
  • C.continue to run at synchronous speed with a larger torque angle
  • D.slip poles and lose synchronism

Answer: D

Correct answer: slip poles and lose synchronism

Beyond pull-out the torque angle passes 90 degrees, where the developed torque begins to fall as the angle grows while the load torque does not. The rotor cannot recover, falls back a pole pitch and then another, drawing heavy pulsating current and producing severe torque pulsations in the shaft. It cannot simply run slower, since torque exists only at synchronous speed, and the machine must be tripped and restarted.

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