Discussion
An induction machine develops 80 N·m at 5 per cent slip on a 1,500 rpm synchronous speed. Its air gap power is nearest
Answer: B
Correct answer: 12.6 kW
Air gap power is the torque multiplied by the synchronous angular velocity, not the actual one: \[ \omega_s = \frac{2\pi \times 1500}{60} = 157.1\ \mathrm{rad/s}, \qquad P_g = 80 \times 157.1 = 12{,}566\ \mathrm{W}. \] The slip does not enter this calculation; it determines how the 12.6 kW then divides between rotor loss and mechanical power.
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