Discussion
A conductor 0.4 m long moves at 15 m/s perpendicular to a field of 0.5 T. The emf developed is
Answer: A
The product is \( 0.5 \times 0.4 \times 15 = 3 \) V. Reversing either the motion or the field reverses the emf, and reversing both leaves it unchanged, which is worth remembering when tracing the polarity of a generator.
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