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The value of \(\sin 5^{o}\sin 10^{o}\sin 15^{o}\sin 20^{o}...\sin 240^{o}\) is equal to

  • A.\(\dfrac{1}{2^{24}}(\sin 15^{o} + \cos 15^{o})\)
  • B.\(\dfrac{1}{2^{12}}(\sin 15^{o} + \cos 15^{o})\)
  • C.\(\dfrac{1}{2^{22}}(\sin 15^{o} + \cos 15^{o})\)
  • D.\(\dfrac{1}{2^{42}}(\sin 15^{o} + \cos 15^{o})\)
  • E.0

Answer: E

The product is 0.

The angles run 5°, 10°, 15°, ..., 240° in steps of 5°, so 180° is one of them. Since \(\sin 180^{\circ} = 0\), the whole product is 0.

The other options are of the form produced by product formulas for sines of angles below 90°; they would apply only if no factor vanished. Spotting a zero factor first is the quick route here.

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