Machine-translated by Google. Questions are authored in English.
Top

Discussion

Taking into consideration of significant figures, in the conversion relation 2.0 ms-2 = X km h-2, the value of X is

  • A.2.6 x \(10^{4}\)
  • B.2.592 x \(10^{4}\)
  • C.2 x \(10^{4}\)
  • D.2.592 x \(10^{5}\)
  • E.2.60 x \(10^{5}\)

Answer: A

\(X\) is \(2.6 \times 10^{4}\).

Convert metres to kilometres and seconds to hours: 1 m = \(10^{-3}\) km and 1 s = \(\frac{1}{3600}\) h, so \(1 \text{ s}^{-2} = 3600^{2} \text{ h}^{-2}\).

\[ \begin{aligned} 2.0 \text{ m s}^{-2} &= 2.0 \times 10^{-3} \times 3600^{2} \\ &= 2.0 \times 12960 \\ &= 25920 \text{ km h}^{-2} \end{aligned} \]

The given value 2.0 has two significant figures, so the answer is rounded to two: \(2.6 \times 10^{4}\).

\(2.592 \times 10^{4}\) is the unrounded value, which claims more precision than the data, and the \(10^{5}\) options misplace the decimal point.

No comment is present. Be the first to comment.
Loading…

Post your comment

Please log in or register to post a comment.