Discussion
The volume of a sphere of radius \( a \) obtained by integrating the spherical volume element is
Answer: A
Integrating \( r^2 \, dr \) from zero to a gives \( a^3/3 \), the sine integral over theta gives two and the phi integral gives \( 2\pi \). The product is \( 4\pi a^3/3 \), which is the standard check on the volume element.
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