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True Discount Questions and Answers

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51.

The true discount on Rs. 3520 due after a certain time at 18% per annum is Rs. 320. The time after which it is due is:

Answer: C

\[ \text{PW} = 3520 - 320 = \text{Rs. } 3200 \]

True discount is simple interest on the present worth:

\[ 320 = \frac{3200 \times 18 \times T}{100} = 576\,T \]

\[ T = \frac{320}{576} = \frac{5}{9} \text{ year} \]

That is about 6 months and 20 days. Using the Rs. 3520 face value in place of the present worth gives \( \tfrac{320}{633.6} = \tfrac{4}{9} \) - exactly the distractor offered.

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52.

The banker's gain on a bill due 3 year hence at 6% per annum is Rs. 18. The true discount is:

Answer: A

Four quantities are related throughout this topic. Writing \( k = \dfrac{RT}{100} \):

\[ \text{BD} = A\,k, \qquad \text{TD} = \frac{A\,k}{1+k} = \text{PW}\,k, \qquad \text{BG} = \text{BD} - \text{TD} = \text{TD}\,k \]

The banker's discount is interest on the face value; the true discount is interest on the present worth; the banker's gain is the interest on the true discount.

Here \( k = \dfrac{6 \times 3}{100} = 0.18 \), and the banker's gain is interest on the true discount:

\[ \text{BG} = \text{TD} \times k \quad\Longrightarrow\quad 18 = \text{TD} \times 0.18 \]

\[ \text{TD} = \frac{18}{0.18} = \text{Rs. } 100 \]

The banker's gain is always the smallest of the four quantities, being interest on the discount rather than on either principal.

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53.

A man buys a watch for Rs. 2825 in cash and sells it for Rs. 3300 at a credit of 1 year. If the rate of interest is 10% per annum, the man gains:

Answer: B

\[ \text{Amount} = \text{PW}\left(1 + \frac{RT}{100}\right), \qquad \text{TD} = \text{Amount} - \text{PW} \]

The Rs. 3300 arrives a year late, so bring it back to today's money before comparing.

\[ \text{PW} = \frac{3300}{1 + \dfrac{10 \times 1}{100}} = \frac{3300}{1.1} = \text{Rs. } 3000 \]

\[ \text{gain} = 3000 - 2825 = \text{Rs. } 175 \]

The raw difference of Rs. 475 looks like the profit, but Rs. 300 of it is merely the price of waiting a year - which is why Rs. 475 is offered as a distractor.

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54.

Find a single discount which is equivalent to three successive discounts of 15%, 16% & 20%.

Answer: C

Multiply the three retained fractions.

\[ (1-0.15)(1-0.16)(1-0.20) = 0.85 \times 0.84 \times 0.80 \]

\[ 0.85 \times 0.84 = 0.714, \qquad 0.714 \times 0.80 = 0.5712 \]

\[ \text{single equivalent discount} = 1 - 0.5712 = 0.4288 = 42.88\% \]

The rates sum to 51%, far above the truth. The order of the three discounts makes no difference, since multiplication is commutative.

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55.

The true discount on Rs. 5125 due 6 months hence is Rs. 125. The rate of interest per annum is:

Answer: A

\[ \text{PW} = 5125 - 125 = \text{Rs. } 5000 \]

The true discount is simple interest on that present worth, over \( T = \dfrac{6}{12} = 0.5 \) year:

\[ 125 = \frac{5000 \times R \times 0.5}{100} = 25R \]

\[ R = \frac{125}{25} = 5\% \text{ per annum} \]

The half-year must be converted before dividing; leaving \( T = 6 \) would give a rate about twelve times too small.

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56.

The simple interest and the true discount on a certain sum for a given time and at a given rate are Rs. 85 and Rs. 80 respectively. The sum due is:

Answer: A

Simple interest is reckoned on the amount, true discount on the present worth, and both use the same rate–time product \( k \):

\[ \text{SI} = A\,k, \qquad \text{TD} = (A - \text{TD})\,k \]

\[ \frac{\text{SI}}{\text{TD}} = \frac{A}{A - \text{TD}} \quad\Longrightarrow\quad \frac{85}{80} = \frac{A}{A - 80} \]

\[ 85A - 6800 = 80A \quad\Longrightarrow\quad 5A = 6800 \quad\Longrightarrow\quad A = \text{Rs. } 1360 \]

The standard shortcut is

\[ \text{Sum} = \frac{\text{SI} \times \text{TD}}{\text{SI} - \text{TD}} = \frac{85 \times 80}{5} = 1360 \]

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57.

A man bought a cow for Rs. 3000 in cash and sold it the same day for Rs. 3660, due 2 years hence. If the rate of interest is 10% per annum, the man gains:

Answer: D

\[ \text{Amount} = \text{PW}\left(1 + \frac{RT}{100}\right), \qquad \text{TD} = \text{Amount} - \text{PW} \]

\[ \text{PW} = \frac{3660}{1 + \dfrac{10 \times 2}{100}} = \frac{3660}{1.2} = \text{Rs. } 3050 \]

\[ \text{gain} = 3050 - 3000 = \text{Rs. } 50 \]

\[ \text{gain}\% = \frac{50}{3000} \times 100 = 1.67\% \]

That figure appears nowhere on the list, so the answer is none of these. It is worth contrasting this with the Rs. 3600 version of the same problem, where the present worth comes to exactly Rs. 3000 and the gain is 0%.

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58.

I purchased a bike for Rs. 1056 in cash and sold it the same day for Rs. 1296, payable after 8 months. If the rate of interest is 12% per annum, what was my gain per cent?

Answer: C

\[ \text{Amount} = \text{PW}\left(1 + \frac{RT}{100}\right), \qquad \text{TD} = \text{Amount} - \text{PW} \]

The Rs. 1296 is payable after 8 months, so \( T = \dfrac{8}{12} = \dfrac{2}{3} \) year at 12%:

\[ \frac{RT}{100} = \frac{12 \times 2/3}{100} = 0.08 \]

\[ \text{PW} = \frac{1296}{1.08} = \text{Rs. } 1200 \]

\[ \text{gain} = 1200 - 1056 = \text{Rs. } 144 \]

\[ \text{gain}\% = \frac{144}{1056} \times 100 = 13.64\% \approx 13.6\% \]

Comparing Rs. 1296 with Rs. 1056 directly suggests 22.7% - the last distractor - but that ignores the eight months of waiting.

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59.

The simple interest on Rs. 750 for 2 years is equal to the true discount on Rs. 810 for the same time and at the same rate. The rate of interest per annum is:

Answer: A

Write \( k = \dfrac{R \times 2}{100} \). Simple interest is on the full sum; true discount is on the present worth:

\[ \text{SI} = 750\,k, \qquad \text{TD} = \frac{810\,k}{1+k} \]

Setting them equal and cancelling \( k \):

\[ 750(1+k) = 810 \quad\Longrightarrow\quad 1+k = 1.08 \quad\Longrightarrow\quad k = 0.08 \]

\[ \frac{2R}{100} = 0.08 \quad\Longrightarrow\quad R = 4\% \]

The two years enter only at the last step; everything before it is independent of the period.

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60.

If Rs. 10 be allowed as true discount on a bill of Rs. 110 due at the end of a certain time, then the discount allowed on the same sum due at the end of double the time is:

Answer: D

First recover the rate–time product from the original bill.

\[ \text{PW} = 110 - 10 = 100 \quad\Longrightarrow\quad 100k = 10 \quad\Longrightarrow\quad k = 0.1 \]

Doubling the time doubles \( k \) to 0.2, so for the same Rs. 110:

\[ \text{PW}' = \frac{110}{1.2} = 91.67 \quad\Longrightarrow\quad \text{TD}' = 110 - 91.67 = \text{Rs. } 18.33 \]

True discount does not double when the time doubles - the Rs. 20 option is exactly that assumption. It grows more slowly, because the present worth it is computed on shrinks at the same time.

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