Puzzle Test Questions and Answers

Answer: B

Clearly, D must be staged on Friday. A must be staged before E i.e., order AE must be followed. But E cannot be staged on last day. Also, B must be staged immediately after F i.e., order FB must be followed. But B cannot precede D. So, F and B can be staged on Monday and Tuesday and A and E on Wednesday and Thursday. C, which cannot be staged on Tuesday shall be staged on Saturday. Thus, the order followed will be :

 F will be played on Monday.
So, the answer is (b).

Answer: D

Clearly, D must be staged on Friday. A must be staged before E i.e., order AE must be followed. But E cannot be staged on last day. Also, B must be staged immediately after F i.e., order FB must be followed. But B cannot precede D. So, F and B can be staged on Monday and Tuesday and A and E on Wednesday and Thursday. C, which cannot be staged on Tuesday shall be staged on Saturday. Thus, the order followed will be :

 Play D is between E and C.
So, the answer is (d).

Answer: E

Clearly, D must be staged on Friday. A must be staged before E i.e., order AE must be followed. But E cannot be staged on last day. Also, B must be staged immediately after F i.e., order FB must be followed. But B cannot precede D. So, F and B can be staged on Monday and Tuesday and A and E on Wednesday and Thursday. C, which cannot be staged on Tuesday shall be staged on Saturday. Thus, the order followed will be :

 Clearly, order of staging of plays in F, B, A, E, D, C.
So, the answer is (e).

Answer: C

Clearly, D must be staged on Friday. A must be staged before E i.e., order AE must be followed. But E cannot be staged on last day. Also, B must be staged immediately after F i.e., order FB must be followed. But B cannot precede D. So, F and B can be staged on Monday and Tuesday and A and E on Wednesday and Thursday. C, which cannot be staged on Tuesday shall be staged on Saturday. Thus, the order followed will be :

C cannot be staged on Friday as well because D has to be staged on that day.

Answer: D

We first form the sequence of visit using (iv), (v) and (vi).
From (iv), we know that Q visits first and U visits last.
From (v), we know that W visits first after break and is followed by R.
From (vi), we know that P visits after break.
Thus, the sequence of visit after break becomes W R P U.
Also, S has the same position in morning session as P in afternoon session. So, sequence of visit before break is Q, T / V, S, V / T.
Clearly, P visits between R and U

Answer: C

We first form the sequence of visit using (iv), (v) and (vi).
From (iv), we know that Q visits first and U visits last.
From (v), we know that W visits first after break and is followed by R.
From (vi), we know that P visits after break.
Thus, the sequence of visit after break becomes W R P U.
Also, S has the same position in morning session as P in afternoon session. So, sequence of visit before break is Q, T / V, S, V / T.
The time of visit of W is 2 p.m. to 3 p.m., that of doctor R is 3 p.m. to 4 p.m.
So, the visit of doctor R is over at 4 p.m.

Answer: C

We first form the sequence of visit using (iv), (v) and (vi).
From (iv), we know that Q visits first and U visits last.
From (v), we know that W visits first after break and is followed by R.
From (vi), we know that P visits after break.
Thus, the sequence of visit after break becomes W R P U.
Also, S has the same position in morning session as P in afternoon session. So, sequence of visit before break is Q, T / V, S, V / T.
Clearly, T visits either second or fourth. So, the time of visit on Saturday will be either 9.30 a.m. or 10.30 a.m.
Thus, T's visit will be over at either 10 a.m. or 11 a.m.

Answer: B

We first form the sequence of visit using (iv), (v) and (vi).
From (iv), we know that Q visits first and U visits last.
From (v), we know that W visits first after break and is followed by R.
From (vi), we know that P visits after break.
Thus, the sequence of visit after break becomes W R P U.
Also, S has the same position in morning session as P in afternoon session. So, sequence of visit before break is Q, T / V, S, V / T.
Clearly, as mentioned, lunch break will be over and doctor W will visit at 1.45 p.m., doctor R will visit at 2.30 p.m., doctor P will visit at 3.15 p.m. and U will visit at 4 p.m.

Answer: B

In a term of six if five boys are to be selected then both A and D together are selected.
If C is selected, a girl Q will be selected.
From B and E, one has to be selected. So, we select E because B will be accompanied by a girl.
The fifth boy will be F. So, the only girl will be Q in the team A C D E F G.
Hence, the answer is (b).

Answer: A

If P is included, D and hence A cannot be included.
If Q is selected, C has to be selected and so S cannot be selected.
T goes with S. So, T is also not selected.
The third girl can be R. With R, B will be selected but with B, E cannot be selected. So, the sixth member can be F only. i.e, the team become P Q C R B F. So, the answer is (a).