Siny=1 is
Answer: B
\( \sin y = 1 \) is non-linear, because the unknown sits inside a sine rather than appearing to the first power on its own.
A linear equation admits the unknown only as \( ay + b \); anything else - a power, a product of unknowns, or a transcendental function of the unknown - makes it non-linear:
\[ 3y + 2 = 0 \;\;\text{linear}, \qquad \sin y = 1,\; y^{2} = 4,\; e^{y} = 3 \;\;\text{non-linear} \]
The practical consequence is that superposition fails: two solutions of a non-linear equation cannot be added to give a third.
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