Calendar Questions and Answers

Answer: D

If the period between the two months is divisible by 7, then that two months will have the same calender .

 (a). Oct + Nov  = 31 + 30 = 61 (not divisible by 7)

(b). Apr + May + Jun + Jul + Aug + Sep + Oct = 30 + 31 + 30 + 31 + 31 + 30 + 31  = 214 (not divisible by 7)

(c). Jun + July + Aug + Sep = 30 + 31 + 31 + 30 = 122 (not divisible by 7)

(d). Apr + May + June = 30 + 31 + 30 = 91 (divisible by 7)

Hence, April and July months will have the same calendar.

Answer: B

Leap years normally come four years apart, but a century year that is not divisible by 400 is skipped.

\[ 1896 \ \rightarrow \ \text{(1900 skipped)} \ \rightarrow \ 1904 \]

\[ 1904 - 1896 = 8 \text{ years} \]

So the maximum gap is 8 years. It happens around 1700, 1800, 1900, 2100 and so on - but not 2000, which is divisible by 400.

Answer: A

Weekend means Saturday & Sunday together. In total we have 52 weeks in a year. So there are 52 weekends in a year.

In normal we have 104 Weekend Days.

 We know that a Each normal year has 365 days or 52 weeks plus one day, and each week has two weekend days, which means there are approximately 104 weekend days each year.
Whereas in a leap year we have 366 days it adds one more day to the year. And what makes the change is the starting day of the year.

Answer: B

Multiples of 4 in a century:

\[ \frac{100}{4} = 25 \]

But the century year at the end is a leap year only if divisible by 400, and in three centuries out of four it is not:

\[ 25 - 1 = 24 \]

So an ordinary century has 24 leap years - the standard figure behind the 5 odd days in 100 years.

Answer: C

We know that,

Odd days --> days more than complete weeks

Number of odd days in 400/800/1200/1600/2000 years are 0.

Hence, the number of odd days in first 1600 years are 0.

Number of odd days in 300 years = 1

Number of odd days in 49 years = (12 x 2 + 37 x 1) = 61 days = 5 odd days

Total number of odd days in 1949 years = 1 + 5 = 6 odd days

Now look at the year 1950

Jan 26 = 26 days = 3 weeks + 5 days = 5 odd days

Total number of odd days = 6 + 5 = 11 => 4 odd days

Odd days :-

0 = sunday ;

1 = monday ;

2 = tuesday ;

3 = wednesday ;

4 = thursday ;

5 = friday ;

6 = saturday

Therefore, Jan 26th 1950 was Thursday.

Answer: C

Each century contributes 24 leap years, since the century year itself is skipped unless divisible by 400.

\[ 24 \times 3 = 72 \]

Only in a 400-year block does one century year qualify, giving 97 leap years in 400 rather than 96.

Answer: D

A calendar repeats once the accumulated odd days come back to zero. 2007 is an ordinary year, so count forward, giving each ordinary year 1 odd day and each leap year 2:

The total returns to 0 after 2017, so the first year whose calendar matches 2007 is 2018. Both must also be non-leap for the match to hold, and 2018 is.

Answer: D

Let us find the day on 1st July, 2004.

2000 years have 0 odd day. 3 ordinary years have 3 odd days.

Jan. Feb. March April May June July

31 + 29 + 31 + 30 + 31 + 30 + 1

= 183 days = (26 weeks + 1 day) = 1 t .

Total number of odd days = (0 + 3 + 1) odd days = 4 odd days. '

:. 1st July 2004 was 'Thursday',-,-

Thus, 1st Monday in July 2004 _as on 5th July.

Hence, during July 2004, Monday fell on 5th, 12th, 19th and 26th. .

Answer: C

Given Year is 2005, Which is a non leap year.

Step 1 : Add +11 to the given year (i.e 2005 + 11) = 2016, Which is a leap year. 

Step 2 : Add +6 to the given year (i.e 2005 + 6) = 2011

Therfore, The calendar for the year 2005 will be same for the year 2011

Answer: A

Only the remainder on division by 7 matters - the odd days.

\[ 350 = 50 \times 7 \quad\Longrightarrow\quad 0 \text{ odd days} \]

350 days is exactly fifty weeks, so the day of the week is unchanged: Saturday.