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Data Interpretation Questions and Answers

Important Instructions
Direction for [ Question No: 131 To 131 ] :

The pie chart shows the percentage of students in a school who play five different sports. Study the chart and answer the questions that follow.

131.

If there is a 20% increase in the number of students who play football, and the total number of students remains the same (1200), what will be the new central angle for the Football sector?

Answer: B

Original number of football students = 25% of 1200 = 300.

A 20% increase means the new number is 300 * 1.20 = 360.

The new percentage of students playing football = \(\frac{360}{1200} \times 100 = 30\)%.

The new central angle = 30% of 360° = 0.30 * 360 = 108°.

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Direction for [ Question No: 132 To 134 ] :

The table represents the demand and production (in thousands of tonnes) of a product for 2 companies A and B.

CompanyDemandProduction
A60005000
B55006000

132.

The demand for the product of company A is what per cent more than its production?

Answer: B

Company A demands 6000 and produces 5000, a shortfall of 1000.

The comparison is against the production:

\[ \frac{6000 - 5000}{5000} \times 100 = 20\% \]

"More than" fixes the base as the smaller quantity; comparing against the demand instead would give 16.67%.

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133.

What is the ratio of the total demand to the total production of both companies?

Answer: D

Total Demand = Demand of A + Demand of B = 6000 + 5500 = 11500 tonnes.

Total Production = Production of A + Production of B = 5000 + 6000 = 11000 tonnes.

Required Ratio = Total Demand : Total Production = 11500 : 11000.

Dividing both by 500 gives the ratio 23 : 22.

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134.

For Company B, the production is what percent more than the demand?

Answer: C

Correct answer: 9.09%

“Percent more than the demand” takes the demand as the base, not the production.

For Company B the demand is 5500 and the production 6000, so the excess is 500.

\[\frac{6000 - 5500}{5500} \times 100 = \frac{500}{5500} \times 100 = 9.09\%\]

Dividing by the production instead would give \(\tfrac{500}{6000}\times 100 = 8.33\%\), which is how much less the demand is than the production - a different quantity, and the usual trap in this question type.

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Direction for [ Question No: 135 To 137 ] :

The line graph shows the profit percentage of two companies, X and Y, over the years. Profit % = [(Income - Expenditure) / Expenditure] * 100. Study the graph and answer the questions that follow.

135.

If the income of Company Y in 2018 was Rs. 600 crores, what was its expenditure in that year?

Answer: B

Profit % = \(\frac{\text{Income} - \text{Expenditure}}{\text{Expenditure}} \times 100\).

Let E be the expenditure.

In 2018, the profit percentage for Company Y was 40%.

40 = \(\frac{600 - E}{E} \times 100\)

0.40 = \(\frac{600}{E} - 1\)

1.40 = \(\frac{600}{E}\)

E = \(\frac{600}{1.4} = \frac{6000}{14} \approx 428.57\) crores.

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136.

If the expenditure of Company X in 2017 and Company Y in 2017 were equal, what was the ratio of their incomes in 2017?

Answer: A

Let the equal expenditure for both companies in 2017 be E.

Income = Expenditure × (1 + \(\frac{\text{Profit %}}{100}\)).

For Company X in 2017, Profit = 45%. Income_X = E × (1 + 0.45) = 1.45E.

For Company Y in 2017, Profit = 50%. Income_Y = E × (1 + 0.50) = 1.50E.

Ratio of Incomes (X:Y) = 1.45E : 1.50E = 1.45 : 1.50 = 145 : 150.

Dividing by 5 gives the ratio 29 : 30.

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137.

If the income of both companies in 2020 was equal, what was the ratio of their expenditures (X:Y)?

Answer: B

Let the equal income be I. Let expenditures be E_X and E_Y.

For X in 2020, Profit=50%. So, I = E_X(1+0.50) = 1.5 E_X.

For Y in 2020, Profit=55%. So, I = E_Y(1+0.55) = 1.55 E_Y.

Therefore, 1.5 E_X = 1.55 E_Y.

The ratio E_X / E_Y = 1.55 / 1.5 = 155 / 150 = 31 / 30.

The ratio is 31:30.

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Direction for [ Question No: 138 To 140 ] :

The table below shows the percentage distribution of 1400 students who passed in an exam from five different cities.

City% of Passed Students
A12%
B18%
C25%
D20%
E25%

139.

The number of students passed from city B is what percentage of the number of students passed from city D?

Answer: C

Since the total number of students is the same for all calculations, we can work directly with the percentages.

Percentage from city B = 18%.

Percentage from city D = 20%.

Required percentage = \(\frac{18}{20} \times 100 = 90\)%.

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140.

What is the difference between the number of students passed from cities C and E combined, and the number of students passed from cities A and B combined?

Answer: B

Percentage for C and E = 25% + 25% = 50%.

Percentage for A and B = 12% + 18% = 30%.

The difference in percentage = 50% - 30% = 20%.

The difference in number of students = 20% of 1400 = 0.20 * 1400 = 280.

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Tags: Data Interpretation Questions and Answers || DI MCQ Questions || Data Analysis Quantitative Aptitude || Data Interpretation GK Questions || DI on Quantitative Aptitude