Calendar Questions and Answers

Answer: B

The year 2004 is a jump year.
In this way, it has 2 odd days.
∴ The day on sixth March, 2005 will be 2 days.

past the day on sixth Walk, 2004.
Yet, sixth March, 2005 is Monday.
∴ sixth March, 2004 is Saturday.

Answer: D

17th June, 1998= (1997 year Period structure 1.1.1998 to 17.6.1998)
Odd days in 1600 year=0.
Odd days in 300 year = (5*3) =1.
97 year has 24 jump year +73 standard years.
= 24*2 + 73*1
= 48 + 73
= 121 odd days
= 17 weeks + 2 odd days = 2 odd days
= 2 odd days.
∴ 1998 years have (0+1+2) = 3 odd days

Jan to June = (31+29+31+30+31)
= 152 days

Add 17 days of June.
= 152 + 17
= 169 days
= 24 weeks + 1 days
= 1 odd day.

∴ Total number of odd day = 3 + 1 = 4 odd days.
Hence 17.06.1998 was Thursday.

Answer: A

fifteenth August,2010 =(2009 years+ Period from 1.1.2010 to 15.8.2010)
Odd days in 1600 years = 0.
Odd days in 400 years = 0.

9 year = (2 jump year +7 conventional years)
= (2*2+7*1) = 11 odd days= 4 odd days

Jan + feb + March + April + May + June + July + august
31+28+31+30+31+30+31+15 = 227 days =(32 weeks +3 days )
= 3 odd days

Aggregate no. of odd days = (0+0+4+3) =7
= 0 odd day

Given day is Sunday.

Answer: B

Only the remainder on division by 7 matters - the odd days.

\[ 61 = 8 \times 7 + 5 \quad\Longrightarrow\quad 5 \text{ odd days} \]

Counting five days on from Monday:

\[ \text{Tue, Wed, Thu, Fri, } \mathbf{Sat} \]

The eight complete weeks return to Monday and contribute nothing.

Answer: A

A year is a leap year if it is divisible by 4, except that a century year must also be divisible by 400.

• \( 800 \div 400 = 2 \) ✓
• \( 1200 \div 400 = 3 \) ✓
• \( 2000 \div 400 = 5 \) ✓
• \( 700 \div 400 = 1.75 \) ✗

So 700 is not a leap year, even though it is divisible by 4. The 400-year rule exists because the tropical year is a little under \( 365.25 \) days.

Answer: C

On 31st December,2005 it was Saturday.
Number of odd days frame the year 2006 to the year 2009=(1+1+2+1)=5 days.

∴ On 31st December 2009 , it was Thursday.
In this way, on first jan, 2010 it is Friday.

Answer: A

Count the odd days up to 15 August 1947.

\[ 1600 \text{ years} \rightarrow 0 \text{ odd days} \]

\[ 300 \text{ years} \rightarrow 1 \text{ odd day} \]

\[ 46 \text{ years} = 35 \text{ ordinary} + 11 \text{ leap} \rightarrow 35 + 22 = 57 \rightarrow 1 \text{ odd day} \]

From 1 January to 15 August 1947 (not a leap year):

\[ 31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 = 227 = 32 \times 7 + 3 \]

\[ \text{total odd days} = 0 + 1 + 1 + 3 = 5 \]

Five odd days corresponds to Friday - India's Independence Day fell on a Friday.

Answer: D

Only the remainder on division by 7 matters - the odd days.

\[ 61 = 8 \times 7 + 5 \quad\Longrightarrow\quad 5 \text{ odd days} \]

Counting five days on from Monday:

\[ \text{Tue, Wed, Thu, Fri, } \mathbf{Sat} \]

The eight complete weeks return to Monday and contribute nothing.

Answer: C

Correct answer: 5

In 100 years there are 24 leap years and 76 ordinary years, since 1900-style century years are not leap.

\[\text{Odd days} = 76 \times 1 + 24 \times 2 = 76 + 48 = 124\]

\[124 = 17 \times 7 + 5\]

So 100 years carry 5 odd days, which is why 200 years carry 3, 300 carry 1 and 400 carry none.

Answer: B

On 31st December, 2005 it was Saturday. 

Number of odd days from 2006 to 2009 = (1 + 1 + 2 + 1) = 5 days. 

On 31st December 2009, it was Thursday.

Thus, on 1st Jan, 2010 it is Friday