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Volume & Surface Areas Questions and Answers

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151.

By converting 900000cm³ into liters, answer will be

Answer: D

One litre is 1000 cubic centimetres.

\[ 900{,}000 \text{ cm}^{3} = \frac{900{,}000}{1000} = 900 \text{ litres} \]

Dividing by 100 or by 10,000 gives 9000 and 90, the two distractors either side. It helps to remember that a cubic metre - 1,000,000 cm³ - is exactly 1000 litres, so 900 litres is a little under a cubic metre.

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152.

A wooden cylinder to be carved is 12 cm long and has a diameter of 45 mm. Taking \( \pi = 3.142 \), its total surface area is

Answer: C

Convert the diameter to centimetres first, then halve it.

\[ 45 \text{ mm} = 4.5 \text{ cm} \quad\Longrightarrow\quad r = 2.25 \text{ cm} \]

\[ \text{TSA} = 2\pi r (r + h) = 2 \times 3.142 \times 2.25 \times (2.25 + 12) \]

\[ = 14.139 \times 14.25 = 201.5 \approx 201 \text{ cm}^{2} \]

Both flat ends count, since the whole cylinder is carved; the curved surface alone would come to about 169.7 cm².

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153.

If 200 liters of orange juice is to be poured in cylindrical drum with diameter of 80cm then depth of orange juice in drum is

Answer: B

Convert the volume to cubic centimetres and halve the diameter, then divide by the cross-sectional area.

\[ 200 \text{ litres} = 200{,}000 \text{ cm}^{3}, \qquad r = 40 \text{ cm} \]

\[ \text{cross-section} = \pi r^{2} = 3.142 \times 1600 = 5027.2 \text{ cm}^{2} \]

\[ \text{depth} = \frac{200{,}000}{5027.2} = 39.78 \text{ cm} \]

The litre-to-cubic-centimetre step is the one that decides the order of magnitude; leaving the volume in litres would give a depth of about 0.04 cm.

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154.

If a rectangular cuboid is 15 cm long, 10 cm wide and 9 cm high, then the total surface area of the cuboid is

Answer: A

A cuboid's total surface area sums its three pairs of faces.

\[ \text{TSA} = 2(lb + bh + hl) \]

\[ = 2(15 \times 10 + 10 \times 9 + 9 \times 15) \]

\[ = 2(150 + 90 + 135) = 2(375) = 750 \text{ cm}^{2} \]

Each product must be counted twice, once for each of the opposite faces - the single sum of 375 is exactly half the answer.

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155.

If a rectangular cuboid is 9cm long and 8cm wide with volume of 450cm³ then height of cuboid in 'cm' is

Answer: B

Rearrange the cuboid volume formula for the missing dimension.

\[ V = l \times b \times h \quad\Longrightarrow\quad h = \frac{V}{l \times b} \]

\[ h = \frac{450}{9 \times 8} = \frac{450}{72} = 6.25 \text{ cm} \]

Checking: \( 9 \times 8 \times 6.25 = 450 \) cm³, as required.

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156.

A closed wooden box has internal dimensions 80 cm long, 48 cm wide and 20 cm deep, and the wood is 4 cm thick. What volume of wood is used in constructing the box?

Answer: B

The wood occupies the space between the outer box and the hollow inside it, so find both volumes and subtract.

The wood is 4 cm thick on every face, so each external dimension exceeds the internal one by \( 2 \times 4 = 8 \) cm:

\[ 88 \times 56 \times 28 \text{ cm} \]

\[ V_{\text{external}} = 88 \times 56 \times 28 = 137{,}984 \text{ cm}^{3} \]

\[ V_{\text{internal}} = 80 \times 48 \times 20 = 76{,}800 \text{ cm}^{3} \]

\[ V_{\text{wood}} = 137{,}984 - 76{,}800 = 61{,}184 \text{ cm}^{3} \]

Adding 4 cm rather than 8 cm to each dimension is the standard error - the thickness is present on both opposite faces.

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157.

Water flows through a pipe of diameter 86 mm at a rate of 5 m/s. The volume of water discharged per minute is

Answer: D

The water leaving in one minute forms a cylinder whose cross-section is the pipe's and whose length is the distance the flow covers in that minute.

\[ d = 86 \text{ mm} = 0.086 \text{ m} \quad\Longrightarrow\quad r = 0.043 \text{ m} \]

\[ \text{length per minute} = 5 \times 60 = 300 \text{ m} \]

\[ V = \pi r^{2} \times 300 = 3.1416 \times (0.043)^{2} \times 300 \]

\[ = 3.1416 \times 0.001849 \times 300 = 1.7429 \text{ m}^{3} \]

Since \( 1 \text{ m}^{3} = 1000 \) litres:

\[ V \approx 1742.87 \text{ litres} \]

The two conversions - millimetres to metres and seconds to minutes - are what set the scale of the answer.

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Answer: A

A pyramid is called a right pyramid when its apex sits directly above the centre of its base, so the axis meets the base at a right angle.

When the apex is displaced sideways, the axis leans and the pyramid is oblique.

The other options name pyramids by the shape of their base - triangular, pentagonal, hexagonal - which is a separate classification altogether. A hexagon-based pyramid can be either right or oblique.

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159.

The volume of a cone whose base diameter is 7 cm and whose height is 14 cm is

Answer: C

Halve the diameter to get the base radius, then use the cone volume formula with \( \pi = \tfrac{22}{7} \).

\[ r = \frac{7}{2} = 3.5 \text{ cm}, \qquad h = 14 \text{ cm} \]

\[ V = \frac{1}{3}\pi r^{2} h = \frac{1}{3} \times \frac{22}{7} \times (3.5)^{2} \times 14 \]

\[ = \frac{1}{3} \times \frac{22}{7} \times 12.25 \times 14 = \frac{1}{3} \times 539 \]

\[ V \approx 180 \text{ cm}^{3} \]

Forgetting the \( \tfrac{1}{3} \) would give the volume of the enclosing cylinder, three times too large.

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160.

A cone has a circular base of radius 6m and volume 84π m³. height of cone is

Answer: A

Rearrange the cone volume formula for the height. The \( \pi \) appears on both sides and cancels.

\[ V = \frac{1}{3}\pi r^{2} h \quad\Longrightarrow\quad 84\pi = \frac{1}{3}\pi (6)^{2} h \]

\[ 84 = \frac{36h}{3} = 12h \]

\[ h = 7 \text{ m} \]

Because the volume is quoted as a multiple of \( \pi \), no decimal approximation is needed anywhere.

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