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Pipes & Cistern Questions and Answers

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81.

A leak in the bottom of a tank can empty the full tank in 6 hours. An inlet pipe fills water at the rate of 4 litres a minute. When the tank is full, the inlet is opened and due to the leak the tank is empty in 8 hours. The capacity of the tank (in litres) is

Answer: C

Let the capacity be \( C \) litres. The leak alone empties it in 6 hours, so it drains \( \tfrac{C}{6} \) litres an hour.

The inlet adds \( 4 \times 60 = 240 \) litres an hour, and the net effect empties the tank in 8 hours:

\[ \frac{C}{6} - 240 = \frac{C}{8} \]

\[ C\left(\frac{1}{6} - \frac{1}{8}\right) = 240 \quad\Longrightarrow\quad \frac{C}{24} = 240 \]

\[ C = 5760 \text{ litres} \]

The inlet rate must be converted from litres per minute to litres per hour to match the other terms.

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82.

An electric pump can fill a tank in 3 hours. Because of a leak in the tank, it took 3 hours 30 min to fill the tank. In what time the leak can drain out all the water of the tank and will make tank empty ?

Answer: D

We can get the answer by subtracting work done by leak in one hour by subtraction of

filling for 1 hour without leak and with leak, as

Work done for 1 hour without leak = 1/3

Work done with leak =

capture1 Dup 5 -78958824
So tank will be empty by the leak in 21 hours.

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83.

A tank can be filled by a tap in 20 minutes and by another tap in 60 minutes. Both the taps are kept open for 10 minutes and then the first tap is shut off. After this, the tank will be completely filled in what time ?

Answer: C

 

How we can solve this question ? First we will calculate the work done for 10 mins, then we will get the remaining work, then we will find answer with one tap work, As Part filled by Tap A in 1 min = 1/20 Part filled by Tap B in 1 min = 1/60 (A+B)'s 10 mins work =

capture2 Dup 3 -66176320

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84.

A cistern can be filled in 9 hours but due to a leak at its bottom it takes 10 hours. If the cistern is full, then the time that the leak will take to make it empty will be ?

Answer: C

Part filled without leak in 1 hour = 1/9

Part filled with leak in 1 hour = 1/10

Work done by leak in 1 hour

=1/9-1/10=190

We used subtraction as it is getting empty.

So total time to empty the cistern is 90 hours

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85.

A tank is filled by three pipes with uniform flow. The first two pipes operating simultaneously fill the tank in the same time during which the tank is filled by the third pipe alone. The second pipe fills the tank 5 hours faster than the first pipe and 4 hours slower than the third pipe. Find the time required by the first pipe to fill the tank ?

Answer: B

Suppose, first pipe alone takes x hours to fill the tank .

Then, second and third pipes will take (x -5) and (x - 9) hours respectively to fill the tank.

As per question, we get

capture4 Dup 3 -98216096

After solving this equation, we get

(x-15)(x+3) = 0,

As value can not be negative, so x = 15

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86.

One pipe can fill a tank three times as fast as another pipe. If together the two pipes can fill the tank in 36 minutes, then the slower pipe alone will be able to fill the tank in

Answer: A

Let the slower pipe alone fill the tank in x minutes

then faster will fill in x/3 minutes.

Part filled by slower pipe in 1 minute = 1/x

Part filled by faster pipe in 1 minute = 3/x

Part filled by both in 1 minute =

capture5 Dup 2 -30107640

x = 36 × 4 = 144 mins

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87.

12 buckets of water fill a tank when the capacity of each tank is 13.5 litres. How many buckets will be needed to fill the same tank, if the capacity of each bucket is 9 litres?

Answer: C

Capacity of the tank = (12*13.5) litres

= 162 litres

Capacity of each bucket = 9 litres.

So we can get answer by dividing total capacity of tank by total capacity of bucket.

Number of buckets needed = (162/9) = 18 buckets

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88.

A tank can be filled by two pipes A and B in 60 minutes and 40 minutes respectively. How many minutes will it take to fill the tank from empty state if B is used for the first half time and then A and B fill it together for the other half.

Answer: D

Let the total time be x mins.

Part filled in first half means in x/2 = 1/40

Part filled in second half means in x/2 =

capture6 Dup 2 -83068520

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89.

Taps A and B can fill a bucket in 12 minutes and 15 minutes respectively. If both are opened and A is closed after 3 minutes, how much further time would it take for B to fill the bucket?

Answer: A

Work in rates: a pipe that fills a tank in \( n \) units of time fills \( \tfrac{1}{n} \) of it per unit, and rates add (an emptying pipe counting negative).

For the first 3 minutes both taps run:

\[ 3\left(\frac{1}{12} + \frac{1}{15}\right) = 3 \times \frac{5 + 4}{60} = \frac{27}{60} = \frac{9}{20} \]

B alone must supply the remaining \( \tfrac{11}{20} \):

\[ t = \frac{11}{20} \times 15 = 8.25 \text{ min} = 8 \text{ min } 15 \text{ s} \]

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90.

Two pipes A and B can fill a tank in 6 hours and 4 hours respectively. If they are opened on alternate hours and if pipe A is opened first, in how many hours, the tank shall be full ?

Answer: B

(A+B)'s 2 hour's work when opened =

capture7 Dup 2 -44728952

Now, its A turn in 5th hour

1/6 work will be done by A in 1 hour

Total time = 4 + 1 = 5 hours

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