Machine-translated by Google. Questions are authored in English.
Top

Problems on Trains Questions and Answers

Important Instructions
91.

A train 110 meters long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?

Answer: B

The man walks toward the train, so the speeds add.

\[ \text{relative speed} = 60 + 6 = 66 \text{ kmph} = 66 \times \frac{5}{18} = \frac{55}{3} \text{ m/s} \]

A man is a point, so only the train's own length is covered:

\[ t = \frac{110 \times 3}{55} = 6 \text{ seconds} \]

Had he walked the same way as the train, the relative speed would be 54 kmph and the answer about 7.3 seconds.

Please log in or register to report this question.

92.

A train speeds past a pole in 15 seconds and a platform 100 m long in 25 seconds. Its length is:

Answer: D

The pole crossing covers the train alone, the platform crossing the train plus 100 m.

\[ L = 15v, \qquad L + 100 = 25v \]

Subtracting:

\[ 100 = 10v \quad\Longrightarrow\quad v = 10 \text{ m/s} \]

\[ L = 15 \times 10 = 150 \text{ m} \]

Please log in or register to report this question.

93.

A train crosses a platform of 120 m in 15 sec, same train crosses another platform of length 180 m in 18 sec. then find the length of the train?

Answer: B

Each crossing covers the train plus that platform.

\[ L + 120 = 15v, \qquad L + 180 = 18v \]

Subtracting:

\[ 60 = 3v \quad\Longrightarrow\quad v = 20 \text{ m/s} \]

\[ L = 15 \times 20 - 120 = 180 \text{ m} \]

Subtraction removes the unknown length in a single step, leaving the speed.

Please log in or register to report this question.

94.

A train crosses a platform of 150 m in 15 sec, same train crosses another platform of length 250 m in 20 sec. then find the length of the train?

Answer: A

Each crossing covers the train plus that platform.

\[ L + 150 = 15v, \qquad L + 250 = 20v \]

\[ 100 = 5v \quad\Longrightarrow\quad v = 20 \text{ m/s} \]

\[ L = 15 \times 20 - 150 = 150 \text{ m} \]

Please log in or register to report this question.

95.

A train 400 m long can cross an electric pole in 20 sec and then find the speed of the train?

Answer: C

An electric pole has no length, so the train covers only its own 400 m.

\[ v = \frac{400}{20} = 20 \text{ m/s} \]

\[ 20 \times \frac{18}{5} = 72 \text{ Kmph} \]

Please log in or register to report this question.

96.

The two trains of lengths 400 m, 600 m respectively, running at same directions. The faster train can cross the slower train in 180 sec, the speed of the slower train is 48 km. then find the speed of the faster train?

Answer: B

Length of the two trains = 600m + 400m 

Speed of the first train = X

Speed of the second train= 48 Kmph 

1000/X - 48 = 180

1000/x - 48 * 5/18 = 180

50 = 9X - 120

X = 68 Kmph 

Please log in or register to report this question.

97.

A 1200 m long train crosses a tree in 120 sec, how much time will I take to pass a platform 700 m long?

Answer: B

A tree is a point, so the first crossing gives the speed.

\[ v = \frac{1200}{120} = 10 \text{ m/s} \]

\[ t = \frac{1200 + 700}{10} = 190 \text{ seconds} \]

Timing only the platform's 700 m would give 70 seconds; the train's own length is part of the crossing.

Please log in or register to report this question.

98.

A train is 360 meter long is running at a speed of 45 km/hour. In what time will it pass a bridge of 140 meter length?

Answer: C

\[ 1 \text{ km/hr} = \frac{5}{18} \text{ m/s} \]

\[ 45 \text{ km/hr} = 12.5 \text{ m/s} \]

\[ t = \frac{360 + 140}{12.5} = \frac{500}{12.5} = 40 \text{ seconds} \]

Please log in or register to report this question.

99.

A train running at the speed of 60 km/hr crosses a pole in 9 seconds. Find the length of the train.

Answer: A

\[ 1 \text{ km/hr} = \frac{5}{18} \text{ m/s} \]

\[ 60 \text{ km/hr} = 60 \times \frac{5}{18} = \frac{50}{3} \text{ m/s} \]

A pole has no length, so the train covers only itself:

\[ L = \frac{50}{3} \times 9 = 150 \text{ metres} \]

Please log in or register to report this question.

100.

How many seconds will a 500 meter long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?

Answer: C

Let length of tunnel is x meter

Distance = 800+x meter

Time = 1 minute = 60 seconds 

Speed = 78 km/hr = 78*5/18 m/s = 65/3 m/s

 Distance = Speed*Time

800+x = (65/3) * 60

800+x = 20 * 65 = 1300

 

x = 1300 - 800 = 500 meters

Please log in or register to report this question.

Loading…
Tags: Problems on Trains Questions and Answers || Problems on Trains MCQ Questions and Answers || Problems on Trains GK Questions and Answers || Problems on Trains GK MCQ Questions || Problems on Trains Multiple Choice Questions and Answers || Problems on Trains GK || GK on Problems on Trains || Quantitative Aptitude Questions and Answers || Quantitative Aptitude MCQ Questions and Answers || Quantitative Aptitude GK Questions and Answers || GK on Quantitative Aptitude