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Arithmetical Reasoning Questions and Answers

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21.

What is the product of all the numbers in the dial of a telephone ?

Answer: D

Correct answer: None of these

A telephone dial carries the digits 0 to 9, and any product containing a zero is zero. So the answer is 0, which is not among the first three options. The item works by inviting the solver to start multiplying 1 through 9 and never notice the zero - and the three plausible-looking six-figure numbers are there to encourage exactly that.

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22.

A is 3 years older to B and 3 years younger to C, while B and D are twins. How many years older is C to D?

Answer: C

Since B and D are twins, so B = D.

Now, A = B + 3 and A = C - 3.

Thus, B + 3 = C - 3 

\(\Rightarrow  D + 3 = C-3\) 

\(\Rightarrow  C - D = 6.\)

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23.

The 30 members of a club decided to play a badminton singles tournament. Every time a member loses a game he is out of the tournament. There are no ties. What is the minimum number of matches that must be played to determine the winner ?

Answer: B

Correct answer: 29

Every match eliminates exactly one player, and 29 of the 30 must be eliminated to leave one winner, so 29 matches are needed - no more and no fewer. The argument holds whatever the draw looks like and whoever wins, which is why byes and uneven brackets make no difference to the total.

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24.

In a garden, there are 10 rows and 12 columns of mango trees. The distance between the two trees is 2 metres and a distance of one metre is left from all sides of the boundary of the garden. The length of the garden is

Answer: C

Correct answer: 24 m

The length runs along the 12 columns, so there are 11 gaps of 2 metres between the outer trees, plus 1 metre of margin at each end: \[ 11\times2 + 1 + 1 = 24\ \mathrm{m}. \] The step to be careful with is that 12 trees make 11 gaps, not 12 - using 12 gives 26, which is offered here.

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25.

12 year old Manick is three times as old as his brother Rahul. How old will Manick be when he is twice as old as Rahul ?

Answer: B

Manick's present age = 12 years, Rahul's present age = 4 years.

Let Manick be twice as old as Rahul after x years from now.

Then, 12 + x = 2 (4 + x) 

\(\Rightarrow  12 + x = 8 + 2x\) 

\(\Rightarrow  x = 4.\)

Hence, Manick's required age = 12 + x = 16 years

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26.

A tailor had a number of shirt pieces to cut from a roll of fabric. He cut each roll of equal length into 10 pieces. He cut at the rate of 45 cuts a minute. How many rolls would be cut in 24 minutes ?

Answer: D

Correct answer: 120 rolls

Cutting a roll into 10 pieces takes 9 cuts, not 10. In 24 minutes he makes \[ 45\times24 = 1080\ \mathrm{cuts}, \qquad \frac{1080}{9} = 120\ \mathrm{rolls}. \] Dividing by 10 instead gives 108, which is offered as a distractor - the same fencepost point as the garden question above.

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27.

In a class of 60 students, the number of boys and girls participating in the annual sports is in the ratio 3 : 2 respectively. The number of girls not participating in the sports is 5 more than the number of boys not participating in the sports. If the number of boys participating in the sports is 15, then how many girls are there in the class ?

Answer: C

Let the number of boys and girls participating in sports be 3x and 2x respectively.

Then, 3x = 15 or x = 5.

So, number of girls participating in sports = 2x = 10.

Number of students not participating in sports = 60 - (15 + 10) = 35.

Let number of boys not participating in sports be y.

Then, number of girls not participating in sports = (35 -y).

Therefore (35 - y) = y + 5 

\(\Rightarrow  2y = 30\) 

\(\Rightarrow  y = 15.\)

So, number of girls not participating in sports = (35 - 15) = 20.

Hence, total number of girls in the class = (10 + 20) = 30

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28.

There are deer and peacocks in a zoo. By counting heads they are 80. The number of their legs is 200. How many peacocks are there ?

Answer: D

Correct answer: 60

With \( d \) deer at four legs and \( p \) peacocks at two: \[ d + p = 80, \qquad 4d + 2p = 200. \] Halving the second gives \( 2d + p = 100 \), and subtracting the first gives \( d = 20 \), so \( p = 60 \). Check: 80 heads and \( 80 + 120 = 200 \) legs.

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29.

A man wears socks of two colours - Black and brown. He has altogether 20 black socks and 20 brown socks in a drawer. Supposing he has to take out the socks in the dark, how many must he take out to be sure that he has a matching pair ?

Answer: A

Correct answer: 3

There are only two colours, so among any three socks two must match - the pigeonhole principle. Two is not enough, since they could be one of each. The count of 20 in each colour is irrelevant to the answer, and it is put there to tempt the solver towards 20 or 21.

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30.

A motorist knows four different routes from Bristol to Birmingham. From Birmingham to Sheffield he knows three different routes and from Sheffield to Carlisle he knows two different routes. How many routes does he know from Bristol to Carlisle ?

Answer: D

Correct answer: 24

The three legs are chosen independently, so the routes multiply: \[ 4 \times 3 \times 2 = 24. \] Adding them gives 9 and is the standard error. Multiplication is right because every one of the four first legs can be followed by any of the three second legs, and each of those twelve combinations by either of the two third legs.

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