If 1,090 cells are generated during the development of a nematode and 131 die by apoptosis, how many remain in the adult?
Answer: B
Subtracting 131 from 1,090 leaves 959, which is the number of somatic cells in the adult hermaphrodite. The constancy of that figure is what made the lineage mappable at all. Every individual worm follows the same developmental script.
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