The shift of the curve(all in meter units if 'L' is length of the long chord and 'R' is the radius of curve) is:-
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Answer: B
The shift is \(L^2/24R\).
When a transition curve is inserted, the circular curve has to be moved inward by the shift
\[ S = \frac{L^2}{24R} \]
where L is the length of the transition curve and R the radius of the circular curve. (The stem calls L the long chord.) \(L^2/6R\) is the offset at the end of the transition curve, four times the shift, and \(L^2/2R\) is the offset of a simple curve, so they are the usual traps.
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