Problems on Ages Questions and Answers

Answer: B

Let the present age of the man be '\(P\)' and son be '\(Q\)',

Given, \( P + Q = 64 \) or \(Q = (64 - P)\)

Now the man says "I am five times as old as you were, when I was as old as you are",
So, \(P = 5[B - (P - Q)]\)

We get \(6P=10Q\)

Substitute value for \(Q\)

\(6P = 10(64 - P),\)
Therefore, \(P\) = 40 and \(Q\) = 24

Answer: B

Let the Father be \(x\) years when he died. 

Average Age 10 years ago be  \(A\)

Total Age 10 years ago = \(6A\)

Total Age after 10 years(Just before father's Death) =  \( 6A + 6*10 = 6A + 60\)

Father Died and Baby was born => the Total number of people in the family is Same (6) 
Baby born today so age of baby = 0
\((6A +60 - x)/6 = 6A/6\)

\(\Rightarrow A + 10 -(x/6) = A \)

\(\Rightarrow x/6 = 10 \)

\(\Rightarrow x = 60\)

Therefore we can conclude that the father was 60 years old when he died.

Answer: C

Let A's age 10 years ago = \(x\) years

Then, B's age 10 years ago = \(2x\) years

\((x + 10) / (2x+ l0) = 3/4 \)

\(\Rightarrow x = 5.\)

So, the total of their present ages =  \((x + 10 + 2x + 10) \)

\(= (3x + 20) = 35\) years

Answer: D

Let Anushka age = \(x \) years

Charu latha 12 yrs older than Anushka so Charu latha age =  \(x=12\)
Kajal is thrice as old as Anushka so Kajal age =  \(3x\)

The ages of Anushka, Kajal and Charu latha together are 57 years 

i.e , \( x + (x+12) + 3x = 57\)

\(\Rightarrow 5x = 45\)

\(\therefore x=9\)

Anushka age = 9
Kajal age =  \(3x = 27\)

Charu latha age = \(x+12 = 21\)

Answer: C

Present total age of the members = 26(5) = 130 years 

Present age of the youngest member = 10 years
Present total age of the remaining four members = 130 - 10 = 120 years

Their average age at the time of the birth of the youngest member =  \(\frac{120-(4*10)}{4}\)

= 30 - 10 = 20 years

Answer: B

Let Raju's age at the time of his marriage =  \(x\) years

Then from given data,

\(\Rightarrow x +8=\frac{6}{5}x\)
   \(x=40\)

Since got married 8 years ago, his present age  = 48

His sister is 10 years younger => 48 - 10 = 38 years.

Answer: B

Let the present ages of Ajay and Vijay be ' \(A\) ' and ' \(V\) ' years respectively.

 \(\Rightarrow A-8= \frac{4}{3}\left ( V-8 \right )\) and   \( A + 8 =\frac{6}{5}\left ( V-8 \right )\)

\(\Rightarrow\frac{3}{4}\left ( A-8 \right )= V-8\) and    \(\frac{5}{6}\left ( A+8 \right )=V+8\)

\(V=\frac{3}{4}\left ( A-8 \right ) + 8=\frac{5}{6}\left ( A+8 \right )-8\)

\(\Rightarrow \frac{3}{4}A-6+8=\)\(\frac{5}{6}A + \frac{20}{3}- 8\)

\(\Rightarrow 10 -\frac{20}{3}=\)\(\frac{10}{12}A -\)\(\frac{9}{12}A\)

\(\Rightarrow \) \(\frac{10}{3}=\) \(\frac{A}{12}\)

\(\Rightarrow A = 40\)

Answer: B

Raj Tarun's age = 0 when he was born.
Then, given his brother is 6 years old.
Then his father is 6 + 32 = 38 when Raj Tarun was born
And his mother is 3 years yonger than his father => so his mother was 35 years old when Raj Tarun was born
and his sister is 25 year younger than his mother 
so Raj Tarun's sister was 10 years old when Raj Tarun was born.

Answer: C

Let the mother's present age be \(x\) years.

Then, the person's present age = \(\frac{2}{5}x\)

\(\frac{2x}{5+8}x=\frac{1}{2}\left ( x+8 \right )\)

\(2(2x+40)=5\left ( x+8 \right )\)

\(x=40\)

Answer: C

Ram age when he was born = 0 years
His brother's age = 6 year

His father's age = brother age + 32years = 6+32 = 38

His mother's age = father's age - 3 = 35
So sister's age = 35-25 = 10years.