Discussion

Ten years ago A was half of B in age. If the ratio of their present ages is 3 : 4, what will be the total of their present ages

Answer: C

Let A's age 10 years ago = \(x\) years

Then, B's age 10 years ago = \(2x\) years

\((x + 10) / (2x+ l0) = 3/4 \)

\(\Rightarrow x = 5.\)

So, the total of their present ages = \((x + 10 + 2x + 10) \)

\(= (3x + 20) = 35\) years

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