Machine-translated by Google. Questions are authored in English.
Top

Letter and Symbol Series Questions and Answers

Important Instructions
131.

Every digit below is paired with the symbol that shares its key. Which term comes fifth?
1!, 2@, 3#, 4$, ?

Answer: A

Correct answer: 5%

Each term pairs a digit with the symbol on the same key: shift-1 gives !, shift-2 gives @, shift-3 gives #, shift-4 gives $. The next digit is 5 and its shifted character is %, so the term is 5%. The two halves are not independent series; the symbol is fixed by the digit, so the whole answer follows from counting to five. Because each symbol is fixed by its digit, the whole answer follows from counting to five; there is no second series to track.

Please log in or register to report this question.

132.

The letters here run past the end of the alphabet while the symbols retreat. Name the next term.
X*, Y&, Z^, A%, ?

Answer: B

Correct answer: B$

The letters run X, Y, Z and then wrap round to A and B. The symbols run through the shifted number keys backwards: shift-8 gives *, shift-7 &, shift-6 ^, shift-5 %, so the next is shift-4, which is $. The term is B$. Both strands change direction relative to the obvious reading - one wraps, the other descends - which is what makes this the hardest of the compound symbol series.

Please log in or register to report this question.

133.

One part of each term never changes. Identify the part that does and complete the run.
M&, O&, Q&, S&, ?

Answer: C

Correct answer: U&

The symbol never changes, so the whole of the pattern is in the letters, which advance two places at a time: M, O, Q, S. The next is U, giving U&. A constant element in a compound series is there to distract; identifying it as constant early removes half the problem. T is the immediately following letter and would fit a single step. A constant element in a compound term carries no information and is placed there to distract, so identifying it as constant is the first move.

Please log in or register to report this question.

134.

The alphabet positions of these letters double at every step and may pass the end. What comes next?
B, D, H, P, ?

Answer: D

Correct answer: F

The alphabet positions double each time: B is 2, D is 4, H is 8, P is 16. Doubling again gives 32, which is beyond the alphabet, so the count wraps round: 32 minus 26 is 6, which is F. The wrap is what makes this hard, because the series suddenly returns to the beginning of the alphabet after climbing steadily. Anyone who stops at 32 without wrapping finds no letter at all and guesses.

Please log in or register to report this question.

135.

Each position here is a little more than double the one before. Which letter follows?
A, C, G, O, ?

Answer: A

Correct answer: E

Each position is double the last plus one: A is 1, C is 3, G is 7, O is 15. Next is 31, which exceeds 26, so it wraps to 31 minus 26, that is 5, which is E. The doubling is easier to see if the positions are written as one less than a power of two: 1, 3, 7, 15, 31. Without the wrap the series has no next term. Writing the positions as 1, 3, 7, 15, 31 shows them to be one less than the powers of two, which makes the next term immediate.

Please log in or register to report this question.

136.

Doubling the position of each letter gives the next, wrapping past Z where necessary. Complete the run.
C, F, L, X, ?

Answer: B

Correct answer: V

The positions double at every step: C is 3, F is 6, L is 12, X is 24. Twice 24 is 48, which wraps round to 48 minus 26, that is 22, giving V. Doubling series reach the end of the alphabet quickly, so a wrap is almost always involved by the fourth or fifth term; expecting one is half the battle. Doubling series pass the end of the alphabet within four or five terms, so a wrap should be expected rather than treated as an irregularity.

Please log in or register to report this question.

137.

This run has already passed the end of the alphabet once. Give the letter that comes next.
D, H, P, F, ?

Answer: C

Correct answer: L

The positions double each time, wrapping when they pass 26. D is 4, H is 8, P is 16, then 32 wraps to 6, which is F. Doubling 32 gives 64, and subtracting 26 twice leaves 12, which is L. The series has already wrapped once before the question mark, which is the clue that the rule involves wrapping at all - without it the fourth term could not be F. The wrap before the question mark is the clue that the alphabet is being treated as a loop; without it the fourth term could not be F.

Please log in or register to report this question.

138.

Each pair below holds two consecutive letters written the wrong way round. Which pair comes fifth?
BA, DC, FE, HG, ?

Answer: D

Correct answer: JI

Each pair is two consecutive letters written in reverse, and the pairs advance two places at a time: BA, DC, FE, HG. The next pair takes J and I, giving JI. The reversal is easy to lose when writing the answer, which is why IJ - the right letters in the wrong order - is the most attractive distractor. The reversal is easy to lose when writing the answer down, which is why the same two letters in the wrong order are always among the options.

Please log in or register to report this question.

139.

Both the pairs and the letters within them descend. Supply the pair that completes the run.
ZY, XW, VU, TS, ?

Answer: A

Correct answer: RQ

The pairs run backwards through the alphabet, two letters at a time, with each pair written in descending order: Z and Y, then X and W, then V and U, then T and S. The next pair is R and Q, giving RQ. Both the direction of the series and the order within each pair are descending, and keeping the two consistent is where the errors arise. Everything descends here, both within each pair and between pairs, so listing the leading letters Z, X, V, T and R first is the safest route.

Please log in or register to report this question.

140.

Each group reverses three consecutive letters, and the groups move forward. Give the next group.
CBA, FED, IHG, ?

Answer: B

Correct answer: LKJ

Each group is three consecutive letters written in reverse, and the groups step forward three places at a time: the highest letters are C, F, I. The next group is built on L, so it reads LKJ. Reading the groups by their first letter - C, F, I, L - reduces the problem to a simple three-step series. JKL has the right letters but restores them to ascending order. Reading the groups by their highest letter reduces the problem to the three-step series C, F, I, L, after which the reversal is mechanical.

Please log in or register to report this question.

Loading…