Puzzle Test Questions and Answers

Answer: C

The four vocal musicians and one actress in the group are given. Two dancers are Shailja and Tanuja. Two violinists are Girija and Vanaja. Since Jalaja and Shailja cannot be violinists. so, remaining two violinists are Tanuja and Pooja.
Clearly, Tanuja is both a violinist andd a dancer.

Answer: A

The minimum time is 6 hours 30 minutes.

The routes are one-way: from R the only train goes to Q, from Q only to P, from P to R or S, and from S to Q or R. So the trip must go R, Q, P, S and back to R.

1. Leave R at 7:00 (first train), reach Q at 8:00.
2. Q's trains leave at 5:00, 7:00, 9:00 ..., so leave at 9:00 and reach P at 10:00.
3. P's trains leave at 8:00, 9:30, 11:00 ..., so leave at 11:00 and reach S at 12:00.
4. S's trains leave every 45 minutes from 8:00: ... 11:45, 12:30. Leave at 12:30 and reach R at 13:30.

From 7:00 to 13:30 is 6 hours 30 minutes. The shorter options count only the 4 hours of travel plus part of the waiting; every connection above is the first one available, so no faster trip exists.

Answer: B

The girls good at Hindi are Kirti and Ashima.

Reshma is good at Mathematics only, and Kirti is weak in Mathematics only, so neither is the girl good at all four subjects or the girl weak in all four. Those two must be Ashima and Jhanvi.

Reshma, Kirti and Ashima do not study in class IX, so Jhanvi is in class IX. The girl good at all subjects studies in class VIII, so she is not Jhanvi: she is Ashima, and Jhanvi is weak in all subjects.

Good at Hindi: Ashima (good at everything) and Kirti (good at everything except Mathematics). Reshma is good at Mathematics only, and Jhanvi is weak in all.

Answer: C

Her second visit must be to F.

Z is first and H is third, so the second clinic is one of F, G, X or Y. G cannot be second, because F must come before G. X cannot be second, because G must come before X (and F before G). Y cannot be second, because F must come before Y.

Only F has no clinic that must precede it, so F must be second. A valid schedule is Z, F, H, G, X, Y, or Z, F, H, Y, G, X.

Answer: B

The French trainer visited on Wednesday. Number the days Sunday = 1 to Saturday = 7. Exactly four trainers come before Usama, so Usama (Chinese) is on day 5. Veer (Hindi) comes three days before the Chinese trainer, so Veer is on day 2. German and French trainers fall between Veer and Usama, on days 3 and 4. Qasim (English) is two days before the German trainer, which gives German on day 3 and Qasim on day 1, so French is on day 4. The Urdu trainer lies between Rahul and Usama and Tanuj is after Usama, so Urdu is on day 6, Rahul on day 7 and Tanuj on day 6. Sohan is not German, so Sohan is on day 4 and Pappu on day 3. Day 4 is Wednesday, the French trainer. German is Tuesday, Hindi Monday and Chinese Thursday.

Answer: D

E has the birthday on Wednesday. The days run Monday to Saturday. Only C has a birthday before F, so C is on Monday and F is on Tuesday. A is on Thursday. The remaining days, Wednesday, Friday and Saturday, belong to B, D and E. B comes immediately after D, so D and B take Friday and Saturday in that order, leaving Wednesday for E. F is on Tuesday, D on Friday and B on Saturday, so none of these can be Wednesday.

Answer: A

S is White. Only two boxes lie between the Brown box P and the Black box, so they are at the two ends. Brown is not at the top, so Black is on top and P is at the bottom. One box lies between Q and the Red box, so Q is the top Black box and the Red box is third.

White is then second. R is not White, so R is the Red box, and the remaining box S is White. Black, Brown and Red belong to Q, P and R.

Answer: C

E is the oldest. F is the youngest in position 6, and D differs from F by one year, so D is fifth. Two persons between A and E mean that they are at positions 1 and 4, since 2 and 5 or 3 and 6 are not possible with D at 5 and F at 6.

B is older than A, so A cannot be first. Then A is fourth and E is first. B and C fill the second and third places with B older than C. So E is the oldest, and A, B and C are not.

Answer: A

N joins the meeting on Friday. Number the days Monday 1 to Saturday 6. ‘Only M has to join the meeting before O’ means M is the only person who comes before O, so M is on Monday and O is on Tuesday. K is on Wednesday. That leaves Thursday, Friday and Saturday for N, P and L.

L joins after P with exactly one person between them, so P and L must be two days apart. Among Thursday, Friday and Saturday the only such pair is Thursday and Saturday, with P on Thursday and L on Saturday. N is left with Friday. P, L and O are therefore all on other days, which rules out options B, C and D.

Answer: B

S got 72 marks. R lives on an even floor that is not 2, so R is on floor 4. Two children live between R and the one with 93 marks, so the 93-mark child is on floor 1. One child lives between the 93-mark and 56-mark children, so 56 marks belong to the child on floor 3. Q got the highest marks, 93, so Q is on floor 1, and S lives immediately above Q on floor 2. T got 35 marks.

The remaining children P and T take floors 3 and 5. The 56-mark child is on floor 3 and T has 35, so T is on floor 5 and P is on floor 3 with 56. R on floor 4 did not get 72, so R has 81, and the last mark, 72, goes to S. P, T and Q hold 56, 35 and 93, so options A, C and D are wrong.