A man walks 2 km towards North. Then he turns to East and walks 10 km. After this he turns to North and walks 3 km. Again he turns towards East and walks 2 km. How far is he from the starting point?
Answer: B
Correct answer: 13 km
The northward legs come to \( 2 + 3 = 5 \) km and the eastward to \( 10 + 2 = 12 \) km. By Pythagoras the distance is \[ \sqrt{5^2 + 12^2} = \sqrt{169} = \mathbf{13}\text{ km} \]
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