Direction Sense Test Questions and Answers

Answer: B

Raviraj starts from home at A, moves 20 Km in south upto B. Then he turns right and moves 10 Km upto C, then he turns right and moves 20 Km upto D, then he turns lefts and moves 20 Km upto E.

So from image it is clear that, if he moves straight then he will have to move AD+DE, AD = BC = 10 Km
So, he will have to move 10 + 20 = 30 Km

Answer: C

the child moves from A to B 90 metres eastwards upto B, then turns right and moves 20 metre upto C, then turns right and moves upto 30 metre upto D. Finally he turns right and moves upto 100 metre upto E.

So AB = 90 metre, BF = CD = 30 metre,
So, AF = AB - BF = 60 metre

Also DE = 100 metre, DF = BC = 20 metre
So, EF = DE - DF = 80 metre

as we can see in image that triangle AFE is a right angled triangle and we are having two sides, need to calculate third one, so we can apply Pythagoras theorem here 

\begin{aligned}
A = AE = \sqrt{AF^2 + EF^2} \\
= \sqrt{(60)^2+(80)^2} \\
= \sqrt{3600+6400} \\
= \sqrt{10000} = 100
\end{aligned}

So from starting point his father was 100 metre away.

Answer: D

Kunal moves from A 10 Km northwards upto B, then moves 6 Km southwards upto C, turns towards east and moves 3 km upto D.
Then AC = (AB-BC) = 4 Km

So Kunal distance from starting point A
\begin{aligned}
AD = \sqrt{AC^2 + CD^2} \\
= \sqrt{4^2+3^2} \\
= \sqrt{25} = 5
\end{aligned}

So AD is 5 Km also with reference to starting point Kunal's direction is North-East.

Answer: C

Correct answer: 60 metres

The northward and southward legs cancel - 20 north and then 20 south - leaving \( 40 + 20 = \mathbf{60} \) metres westward.

Answer: B

Correct answer: North

Starting eastward, the two right turns bring him first to south and then to west; the two left turns that follow bring him to south again and then to east - and the last left turn leaves him facing north.

Answer: A

Correct answer: North-East

Facing south, a right turn brings me west. The legs then come to 20 + 10 = 30 west against 60 east, leaving 30 east, and 10 + 20 = 30 north. Being both east and north of the start, I am to its north-east.

Answer: C

Rohit's distance from the starting point A will be
AE = AD+DE = 20 + 15 = 35 metre

And direction with reference to the starting point is east

Answer: B

Correct answer: 10 metres, West

The southward and northward legs cancel - 20 south and then 20 north - while the sideways moves are 30 east and 40 west. Q therefore lies \[ 40 - 30 = \mathbf{10}\text{ metres west} \] of P.

Answer: B

Correct answer: North

The eastward and westward legs cancel, leaving \( 15 - 5 = 10 \) kms northward - so he is to the north of his house.

Answer: D

Correct answer: At the starting Point

The south-west and north-west legs carry her equally south and north, so those parts cancel; what is left of them carries her back westward over the ground covered by the first leg, bringing her round to the point she started from.