It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010 ?
Answer: B
Only the remainder on division by 7 matters - the odd days.
Count the odd days from 1 January 2006 to 1 January 2010.
\[ 2006:1, \quad 2007:1, \quad 2008:2 \text{ (leap)}, \quad 2009:1 \]
\[ \text{total} = 5 \text{ odd days} \]
\[ \text{Sunday} + 5 = \textbf{Friday} \]
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On 24th Nov, 2007 Thursday falls. What day of the week was it on 10th Nov, 2006 ?
Answer: A
The year 2006 is an ordinary year. So, it has 1 odd day.
So, the day on 24th Nov, 2007 will be 1 day beyond the day on 24th Nov, 2006.
But, 24th Nov, 2007 is Thursday.
24 - 10 = 14 days.
Therefore, 2 weeks ago it is same day.
Thus, 10th Nov, 2006 is one day before 10th Nov, 2007 i.e. it is Wednesday.
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On 19th June, 1984 Monday falls. What day of the week was it on 19th June, 1985?
Answer: C
The year 1985 is an ordinary year. So, it has 1 odd day.
So, the day on 19th June, 1985 will be 1 day after the day on 19th June, 1984.
But, 19th June,1984 is Monday
S0, 19th June, 1985 is Tuesday.
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How many seconds in 10 years?
Answer: B
We know that,
1 year = 365 days
1 day = 24 hours
1 hour = 60 minutes
1 minute = 60 seconds.
Then, 1 year = 365 x 24 x 60 x 60 seconds.
= 8760 x 3600
1 year = 31536000 seconds.
Hence, 10 years = 31536000 x 10 = 315360000 seconds.
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If 5th March, 2005 is Monday, what was the day of the week on 5th March, 2004 ?
Answer: A
The year 2004 is a leap year. So, it has 2 odd days.
But, Feb 2004 not included because we are calculating from March 2004 to March 2005. So it has 1 odd day only.
The day on 5th March, 2005 will be 1 day beyond the day on 5th March, 2004.
Given that, 5th March, 2005 is Monday.
5th March, 2004 is Sunday (1 day before to 5th March, 2005).
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How old are you if you are born in 1995?
Answer: B
If the month in which you are born is completed in the present year i.e, your birthday, then
Your Age = Present year - Year you are born
As of now, present year = 2018
i.e, Age = 2018 - 1995 = 23 years.
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What is two weeks from today?
Answer: A
We know that the day repeats every 7 days, 14 days, 21 days,...
So if today is Monday, after 7 days it is again Monday, after 14 days again it is Monday.
Hence, after 2 weeks i.e, 14 days the day repeats and is the same day.
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The calendar of year 1939 is same as which year?
Answer: C
1939 is an ordinary year. Counting odd days forward until they total a multiple of seven:
\[ 1939:1,\ 1940:2,\ 1941:1,\ 1942:1,\ 1943:1,\ 1944:2,\ 1945:1,\ 1946:1,\ 1947:1,\ 1948:2,\ 1949:1 \]
\[ \text{total} = 14 \quad\Longrightarrow\quad 0 \text{ odd days} \]
So 1939's calendar repeats in 1950 - the usual 11-year gap for an ordinary year with three leap years in between.
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What was the day on 2nd Jan 1901 ?
Answer: B
2nd Jan 1901 means
(1900 years and 2 day)
Now, 1600 years have 0 odd day
300 years have 1 odd day
2 days has 2 odd day
Total no. of odd days = 0 + 1 + 2 = 3 days
Hence, the day on 2nd Jan 1901 was Wednesday.
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What will be the day of the week 15th August, 2010?
Answer: A
Count the odd days up to the date.
2000 years. Complete centuries in multiples of 400 leave no odd days, so 2000 years contribute 0.
2001 to 2009. Nine years of which 2004 and 2008 are leap:
\[ 7(1) + 2(2) = 11 \equiv 4 \pmod 7 \]
1 January to 15 August 2010. 2010 is ordinary:
\[ 31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 = 227 \equiv 227 - 224 = 3 \pmod 7 \]
\[ \text{total odd days} = 0 + 4 + 3 = 7 \equiv 0 \pmod 7 \]
Zero odd days corresponds to Sunday.
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