1.Number of customers who waited less than 15 minutes in line is 12The largest amount of time in minutes a customer waited in line is 19The least amount of time in minutes a customer waited in line is 102.Number of customers waited less than 15 minutes in line is 12The largest amount of time in minutes a customer waited in line is 19The least amount of time in minutes a customer waited in line is 53.Number of customers who waited less than 15 minutes in line is 15The largest amount of time in minutes a customer waited in line is 19The least amount of time in minutes a customer waited in line is 5In how many of the above rows is the given information correctly tabulated?

The information is correct in only one row.From the data, 3 + 2 + 1 + 4 + 2 = 12 customers waited less than 15 minutes (the 5, 6, 8, 10 and 13 minute values). The longest wait is 19 minutes and the shortest is 5 minutes. The counts add to 16, as the title says.Row 1 gives the least time as 10; it is 5. Wrong.Row 2: 12, 19 and 5. All correct.Row 3 gives 15 customers under 15 minutes, which counts the three customers who waited exactly 15; 'less than 15' excludes them. Wrong.

Statistics (Mean, Median, Mode) Questions and Answers

Q: What is the mean of the first five natural numbers?

The first five natural numbers are 1, 2, 3, 4, and 5.The mean (average) is the sum of the numbers divided by the count of the numbers.Sum = 1 + 2 + 3 + 4 + 5 = 15.Count = 5.Mean = \(\frac{15}{5} = 3\).

Q: What is the mode of the following data set: 2, 4, 6, 4, 7, 4, 8, 9?

The mode is the value that occurs most often.\[ 4 \text{ appears three times; every other value appears once} \]So the mode is 4.

Q: The mean weight of 10 students is 55 kg. If a student with weight 60 kg joins the group, what is the new mean weight?

Original sum of weights = 10 × 55 = 550 kg.Weight of the new student = 60 kg.New total weight = 550 + 60 = 610 kg.New number of students = 10 + 1 = 11.New mean weight = \(\frac{610}{11} \approx 55.45\) kg.

Q: Which measure of central tendency is most affected by extreme values (outliers)?

The mean is the most sensitive to extreme values because its calculation involves the sum of all values. A very large or very small value can significantly pull the mean in its direction.The median is resistant to outliers because it only depends on the middle value(s).The mode is also resistant as it depends only on the frequency of values.

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Consider the following information:

Time in Minutes that 16 Customers Waited in Line

Minutes	5	6	8	10	13	15	19
Customers	3	2	1	4	2	3	1

1.	Number of customers who waited less than 15 minutes in line is 12	The largest amount of time in minutes a customer waited in line is 19	The least amount of time in minutes a customer waited in line is 10
2.	Number of customers waited less than 15 minutes in line is 12	The largest amount of time in minutes a customer waited in line is 19	The least amount of time in minutes a customer waited in line is 5
3.	Number of customers who waited less than 15 minutes in line is 15	The largest amount of time in minutes a customer waited in line is 19	The least amount of time in minutes a customer waited in line is 5

In how many of the above rows is the given information correctly tabulated?

A.Only one
B.Only two
C.All three
D.None

Exam Year(s)

Haryana Civil Services - 2026, HPSC - 2026,

Answer: A

The information is correct in only one row.

From the data, 3 + 2 + 1 + 4 + 2 = 12 customers waited less than 15 minutes (the 5, 6, 8, 10 and 13 minute values). The longest wait is 19 minutes and the shortest is 5 minutes. The counts add to 16, as the title says.

Row 1 gives the least time as 10; it is 5. Wrong.
Row 2: 12, 19 and 5. All correct.
Row 3 gives 15 customers under 15 minutes, which counts the three customers who waited exactly 15; 'less than 15' excludes them. Wrong.

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What is the mean of the first five natural numbers?

A.2
B.2.5
C.3
D.3.5

Answer: C

The first five natural numbers are 1, 2, 3, 4, and 5.

The mean (average) is the sum of the numbers divided by the count of the numbers.

Sum = 1 + 2 + 3 + 4 + 5 = 15.

Count = 5.

Mean = \(\frac{15}{5} = 3\).

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Find the median of the following set of numbers: 7, 3, 5, 8, 2.

Answer: B

To find the median, we first need to arrange the numbers in ascending order.

Arranged set: 2, 3, 5, 7, 8.

The median is the middle value. In this set of 5 numbers, the middle value is the 3rd term, which is 5.

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What is the mode of the following data set: 2, 4, 6, 4, 7, 4, 8, 9?

Answer: B

The mode is the value that occurs most often.

\[ 4 \text{ appears three times; every other value appears once} \]

So the mode is 4.

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The mean of 5 numbers is 20. If one number is excluded, the mean of the remaining numbers becomes 23. What is the excluded number?

A.8
B.12
C.15
D.20

Answer: A

The sum of the original 5 numbers = Mean × Count = 20 × 5 = 100.

After one number is excluded, there are 4 numbers left, and their mean is 23.

The sum of the remaining 4 numbers = 23 × 4 = 92.

The excluded number is the difference between the original sum and the new sum.

Excluded number = 100 - 92 = 8.

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Find the median of the data: 12, 15, 16, 10, 8, 19.

A.12
B.13.5
C.15
D.16

Answer: B

First, arrange the data in ascending order: 8, 10, 12, 15, 16, 19.

Since there is an even number of observations (6), the median is the average of the two middle values (the 3rd and 4th terms).

Middle values are 12 and 15.

Median = \(\frac{12 + 15}{2} = \frac{27}{2} = 13.5\).

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A batsman scores 35, 45, 38, 42, and x runs in five innings. If his average score for the five innings is 40, what is the value of x?

A.38
B.40
C.42
D.44

Answer: B

The mean (average) score is the total score divided by the number of innings.

Total score = 35 + 45 + 38 + 42 + x = 160 + x.

Average = \(\frac{160 + x}{5} = 40\).

160 + x = 40 × 5 = 200.

x = 200 - 160 = 40.

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What is the relationship between mean, median, and mode for a moderately skewed distribution?

A.Mode = 3 median - 2 mean
B.Mean = 3 median - 2 mode
C.Median = 3 mode - 2 mean
D.Mode = 2 median - 3 mean

Answer: A

For a moderately skewed distribution the three averages satisfy the empirical relation

\[ \text{Mode} = 3\,\text{Median} - 2\,\text{Mean} \]

It says the mode lies about twice as far from the mean as the median does, on the same side.

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The mean weight of 10 students is 55 kg. If a student with weight 60 kg joins the group, what is the new mean weight?

A.55 kg
B.55.45 kg
C.56 kg
D.57.5 kg

Answer: B

Original sum of weights = 10 × 55 = 550 kg.

Weight of the new student = 60 kg.

New total weight = 550 + 60 = 610 kg.

New number of students = 10 + 1 = 11.

New mean weight = \(\frac{610}{11} \approx 55.45\) kg.

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10.

Which measure of central tendency is most affected by extreme values (outliers)?

A.Mean
B.Median
C.Mode
D.Range

Answer: A

The mean is the most sensitive to extreme values because its calculation involves the sum of all values. A very large or very small value can significantly pull the mean in its direction.

The median is resistant to outliers because it only depends on the middle value(s).

The mode is also resistant as it depends only on the frequency of values.

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Other Subjects

Tags: Statistics Mean, Median, Mode Questions || Data Statistics MCQ || Mean and Median GK || Mode Problems Quantitative Aptitude || Statistics Quantitative Aptitude MCQs

Statistics (Mean, Median, Mode) Questions and Answers

Important Instructions

Direction for [ Question No: 1 To 1 ] :

Topics

Other Subjects

Tags: Statistics Mean, Median, Mode Questions || Data Statistics MCQ || Mean and Median GK || Mode Problems Quantitative Aptitude || Statistics Quantitative Aptitude MCQs

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