Can you use the fprintf() to display the output on the screen?
Answer: A
Correct answer: Yes
fprintf writes to whatever stream it is given, and stdout is a stream like any other - so fprintf(stdout, "...") prints to the screen, exactly as printf does. Indeed printf(...) is defined as fprintf(stdout, ...).
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What will the function randomize() do in Turbo C under DOS?
Answer: D
Correct answer: returns a random number generator with a random value based on time
randomize() seeds the random number generator from the system clock, so that a program produces a different sequence on each run. Without it, rand() starts from the same seed every time and repeats the same numbers - which is convenient for debugging and useless for a game.
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What will be the output of the program?
#include <stdio.h>
int main()
{
int i;
i = printf("How r u\n");
i = printf("%d\n", i);
printf("%d\n", i);
return 0;
}
Answer: B
In the program, printf() returns the number of charecters printed on the console
i = printf("How r u\n"); This line prints "How r u" with a new line character and returns the length of string printed then assign it to variable i.
So i = 8 (length of '\n' is 1).
i = printf("%d\n", i); In the previous step the value of i is 8. So it prints "8" with a new line character and returns the length of string printed then assign it to variable i. So i = 2 (length of '\n' is 1).
printf("%d\n", i); In the previous step the value of i is 2. So it prints "2".
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What will be the output of the program?
#include <stdio.h>
#include<math.h>
int main()
{
float i = 2.5;
printf("%f, %d", floor(i), ceil(i));
return 0;
}
Answer: C
Both ceil() and floor() return the integer found as a double.
floor(2.5) returns the largest integral value(round down) that is not greater than 2.5. So output is 2.000000.
ceil(2.5) returns 3, while converting the double to int it returns '0'.
So, the output is '2.000000, 0'.
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What will be the output of the program?
#include <stdio.h>
int main()
{
int i;
i = scanf("%d %d", &i, &i);
printf("%d\n", i);
return 0;
}
Answer: B
Correct answer: 2
scanf returns the number of items successfully converted and assigned, not the values themselves. Two conversions succeed here, so it returns 2, and that is what is stored in i and printed - overwriting whatever the two conversions had put there.
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What will be the output of the program?
#include <stdio.h>
int main()
{
int i;
char c;
for(i=1; i<=5; i++)
{
scanf("%c", &c); /* given input is 'b' */
ungetc(c, stdout);
printf("%c", c);
ungetc(c, stdin);
}
return 0;
}
Answer: C
The ungetc() function pushes the character c back onto the named input stream, which must be open for reading.
This character will be returned on the next call to getc or fread for that stream.
One character can be pushed back in all situations.
A second call to ungetc without a call to getc will force the previous character to be forgotten.
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What will be the output of the program?
#include <stdio.h>
#include <stdlib.h>
int main()
{
char *i = "55.555";
int result1 = 10;
float result2 = 11.111;
result1 = result1+atoi(i);
result2 = result2+atof(i);
printf("%d, %f", result1, result2);
return 0;
}
Answer: C
Function atoi() converts the string to integer.
Function atof() converts the string to float.
result1 = result1+atoi(i);
Here result1 = 10 + atoi(55.555);
result1 = 10 + 55;
result1 = 65;
result2 = result2+atof(i);
Here result2 = 11.111 + atof(55.555);
result2 = 11.111 + 55.555000;
result2 = 66.666000;
So the output is "65, 66.666000" .
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What will be the output of the program?
#include <stdio.h>
#include <string.h>
int main()
{
char dest[] = {97, 97, 0};
char src[] = "aaa";
int i;
if((i = memcmp(dest, src, 2))==0)
printf("Got it");
else
printf("Missed");
return 0;
}
Answer: B
memcmp compares the first 2 bytes of the blocks dest and src as unsigned chars. So, the ASCII value of 97 is 'a'.
if((i = memcmp(dest, src, 2))==0) When comparing the array dest and src as unsigned chars, the first 2 bytes are same in both variables.so memcmp returns '0'.
Then, the if(0=0) condition is satisfied. Hence the output is "Got it".
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What will function gcvt() do?
Answer: B
Correct answer: Convert floating-point number to a string
gcvt() converts a floating-point number to a string, in the shorter of fixed and exponential notation for the requested number of significant digits. It is a non-standard function of the old Unix and Turbo C libraries; sprintf is the portable way to do the same thing.
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What will be the output of the program?
#include <stdio.h>
int main()
{
int i;
char c;
for(i=1; i<=5; i++)
{
scanf("%c", &c); /* given input is 'a' */
printf("%c", c);
ungetc(c, stdin);
}
return 0;
}
Answer: B
Correct answer: aaaaa
ungetc pushes the character back onto the input stream, so the next scanf reads the same character again. The loop therefore reads and prints the same a on all five passes, giving aaaaa. Only one character of pushback is guaranteed, which is all this needs.
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