Discussion
What will be the output of the program?
#include <stdio.h>
int main()
{
int i;
char c;
for(i=1; i<=5; i++)
{
scanf("%c", &c); /* given input is 'a' */
printf("%c", c);
ungetc(c, stdin);
}
return 0;
}
Answer: B
Correct answer: aaaaa
ungetc pushes the character back onto the input stream, so the next scanf reads the same character again. The loop therefore reads and prints the same a on all five passes, giving aaaaa. Only one character of pushback is guaranteed, which is all this needs.
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