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Problems on Ages Questions and Answers

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91.

The sum of the ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child ?
 

Answer: B

Let the age of the youngest child is '\(x \)' years.
Then the child elder than the yongest is '\(x + 3\)' yrs
Since each have 3yrs difference upto 5 children
And given that,

\(\Rightarrow x +x +3 + x+6 +x+9 + x+12 = 50\)

\(\Rightarrow 5x+30=50\)

\(\Rightarrow x= 4\) years.

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92.

Today is Varun's birthday. One year, from today he will be twice as old as he was 12 years ago. How old is Varun today ?

Answer: B

Let varun's age = \(x\) years.

From the given conditions,

\(\Rightarrow x+1 = 2(x-12)\)

\(\Rightarrow x=25\) years. 
 

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93.

A is three times as old as B. C was twice-as old as A four years ago. In four years' time, A will be 31. What are the present ages of B and C ?

Answer: C

Let the age of A = \(A\), B = \(B\) and C = \(C\)

From given,

\(A = 3B\)

4 years ago,

\(A + 4 = 31\)

\(\Rightarrow A=27\)

sub in above \(B\) , we get \(B\)  = 9 

\(C = 2(27 - 4) + 4 = 46 + 4 = 50 \)

Hence B = 9years and C = 50years.

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94.

The average age of 80 boys in a class is 15. The average age of group of 15 boys in the class is 16 and the average of another 25 boys in the class is 14. What is the average age of the remaining boys in the class ?
 

Answer: D

otal ages of 80 boys = 15 x 80 = 1200 yrs.
Total age of 16 boys = 15 x 16 = 240 yrs
Total age of 25 boys = 14 x 25 = 350 yrs.
Average age of remaining boys = \(1200 - \frac{240+350}{80}-\left ( 25+15 \right )\)=  \(\frac{610}{41}\)

= 15.25 yearss


 

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