Discussion

A is three times as old as B. C was twice-as old as A four years ago. In four years' time, A will be 31. What are the present ages of B and C ?

Answer: C

Let the age of A = \(A\), B = \(B\) and C = \(C\)

From given,

\(A = 3B\)

4 years ago,

\(A + 4 = 31\)

\(\Rightarrow A=27\)

sub in above \(B\) , we get \(B\) = 9

\(C = 2(27 - 4) + 4 = 46 + 4 = 50 \)

Hence B = 9years and C = 50years.

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