Alphabet Test Questions and Answers

Answer: A

Correct answer: X

The fifteenth letter from the left is O, at position 15.

Nine to the right of O is position 24:

\[ 15 + 9 = 24 \rightarrow X \]

Counting the letters confirms it: P, Q, R, S, T, U, V, W, X. The count begins with the letter after O, which is the convention used consistently through this set - the same one that makes the seventh to the right of M come out as T elsewhere.

Answer: B

Correct answer: L

Seventeen letters counted from the end run from Z back to J, positions 10 to 26. Fourteen from the beginning run from A to N, positions 1 to 14.

The overlap is J to N, positions 10 to 14, and its middle is

\[ \frac{10+14}{2} = 12 \rightarrow L \]

As with the companion questions, the two counts overlap in the middle of the alphabet rather than meeting end to end, and it is the shared stretch whose midpoint is wanted.

Answer: D

Correct answer: 24

Build the positions from the front. Ramu is 5th. Rani is six places after him, so Rani is 11th.

Rani is midway between Ramu and Raju, so Raju is as far beyond Rani as Rani is beyond Ramu - six more places, putting Raju 17th from the front.

Raju is also 8th from the last, so the class holds

\[ 17 + 8 - 1 = 24 \]

The subtraction avoids counting Raju twice, once from each end.

Answer: C

Correct answer: U

Write out the arrangement. A to M keep positions 1 to 13, and N to Z reversed occupy 14 to 26:

A B C D E F G H I J K L M Z Y X W V U T S R Q P O N

The 17th letter from the right is at position 10, which is J. Nine to the right of J is position 19:

\[ 10 + 9 = 19 \rightarrow U \]

Only the second half is reversed, so the first thirteen positions are untouched and J is where it always was.

Answer: C

When positions of first and the third alphabets of each of the words are interchanged, we have 
PAL TUB RAC NOS DIH
clearly, PAL and TUB are the only meaningful words. These words are obtained from LAP and BUT
respectively.

Answer: A

Correct answer: L

Two pairs in LEMON match by distance, and the question's phrasing points to the one running forwards. L is at position 1 and O at position 4, three apart in the word; in the alphabet L is 12th and O is 15th, again three apart.

Of those two letters L comes earlier in the alphabet, so L is the answer.

The other matching pair, O and N, is adjacent in both word and alphabet but runs backwards.

Answer: D

Correct answer: U

Strike out every A from the arrangement and read the remainder:

C U B E D E D B E B U C D B C D B D U B C C B E D

Counting from the left: C, U, B, E, D, E, D, B, E, B, U. The eleventh letter is U.

The deletions must be made before counting - in the original arrangement the eleventh symbol is E, so counting first gives the wrong answer.

Answer: D

Specified letters from the left are N and O , and the letter from the right is I.
With these letters , according to the conditions given in the question , one Word ONION can be formed.
Clearly , first letter of this word is O.

Answer: A

Correct answer: 3

The test is that the gap between two letters in the word equals the gap between them in the alphabet, with the second letter later in the alphabet as well.

In CREATIVE three pairs qualify: C and E at positions 1 and 3, two apart in the word and two in the alphabet (3 and 5); T and V at positions 5 and 7, two apart in both (20 and 22); and A and E at positions 4 and 8, four apart in both (1 and 5).

Working through the pairs by separation - adjacent, then two apart, and so on - is the systematic way to be certain none is missed.