The sum of the present ages of a mother and his daughter is 60 years. five years ago, mother's age was four times the age of the daughter. so now the daughter's age will be?
Answer: C
Let the present ages of daughter and mother be \(x\) and \((60-x)\) respectively .
Then, \((60 - x) - 5= 4(x - 5)\)
\(\Rightarrow\) \(55 - x = 4x - 20 \)
\(\Rightarrow \) \(5x=75\)
\(\Rightarrow x=15\)
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Six years ago Anita was P times as old as Ben was. If Anita is now 17 years old, how old is Ben now in terms of P ?
Answer: A
Let Ben’s age now be \(B
\)
Anita's age now be \(A\)
\((A - 6) = P(B - 6)\)
But \(A\) is 17 and therefore, \(11 = P(B - 6)\)
\(\Rightarrow 11/P = B-6\)
\(\Rightarrow (11/P) + 6 = B\)
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The ratio of the present ages of P and Q is 3 : 4. Five years ago, the ratio of their ages was 5 : 7. Find their present ages.
Answer: B
As the ratio of their present ages is 3 : 4 , let their present ages be \(3x\) and \(4x\) respectively.
So, 5 years ago, as the ratio of their ages was 5 : 7, we can write \((3x-5) : (4x-5) = 5 : 7\)
Solving, we get \(x=10\)
Hence, their present ages are \(3x = 30\) and \(4x=40\)
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The ratio of the ages of Maala and Kala is 4 : 3. The total of their ages is 2.8 decades. The proportion of their ages after 0.8 decades will be [1 Decade = 10 years]
Answer: D
Let, Maala’s age = \(4A\) and Kala's age = \(3A\)
Then, \(4A + 3A =28\)
\(A=4\)
Maala’s age = 16 years
and Kala’s age = 12 years
Proportion of their ages after 8 is = \((16 + 8) : (12 + 8)\)
\(=24:20\)
\(=6:5\)
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The ages of Krish and Vaibhav are in the proportion of 3 : 5. After 9 years, the proportion of their ages will be 3 : 4. Then the current age of Vaibhav is:
Answer: C
Let Krish's age be \(3A\) and Vaibhav's age be \(5A\)
\(\therefore(3A+9)/(5A+9) = 3/4\)
\(\Rightarrow 4 (3A + 9) = 3 (5A + 9) \)
\(\Rightarrow A=3\)
Therefore, Vaibhav’s age = 15 years.
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Sivagami is 2 years elder than Meena. After 6 years the total of their ages will be 7 times . Then age of Sivagami is :
Answer: D
Let Meena’s age = \(A\)
Then Sivagami’s age = \(A+2\)
After 6 years the total of their ages will be 7 times of what?
Not clear.
So the given data are inadequate.
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The age of a person is thrice the total ages of his 2 daughters. 0.5 decades hence, his age will be twice of the total ages of his daughters. Then what is the father’s current age? [0.5 Decades = 5 Years]
Answer: C
Let, Total of current ages of the 2 daughters is \(A\) years.
Then, father’s current age = 3A years.
\((3A + 5) = 2 (A +10)\)
\(\Rightarrow\) \(3A + 5 = 2A + 20\)
\(\Rightarrow A = 15\)
Therefore, father’s current age = 45 years.
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0.1 decates ago, Vijaya was quadrice as old as her daughter Simran. 0.6 decades hence, Vijaya’s age will beat her daughter’s age by 0.9 decades. The proportion of the current ages of Vijaya and Simran is : [ 0.1 Decates =1 Year; quadrice = 4 times]
Answer: D
Let, Ages of Vijaya and Simran – 1 year ago was \(4A\) and \(A\) years respectively.
Then, \([(4A + 1) + 6] - [(A + 1) + 6] = 9\)
\(\Rightarrow3A = 9 \)
\(\Rightarrow A=3\)
Needed Ratio = \((4A + 1) : (A + 1) = 13 : 4\)
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A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is
Answer: C
Let the son's present age be \(x\) years .
Then, man's present age = \((x + 24) \) years
\(\Rightarrow (x + 24) + 2 = 2(x + 2)\)
\(\Rightarrow x + 26 = 2x + 4\)
So, \(x = 22\)
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If two times of the daughter’s age in years is included to the mother’s age, the total is 70 and if two times of the mother’s age is included to the daughter’s age, the total is 95. So the Mother’s age is,
Answer: C
Let daughter’s age = \(A\) and mother’s age = \(B\) years
Given: \(2A+B = 70\) and \(A+2B = 95\)
Solving B , we will get \(B=40\)
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