Profit & Loss Questions and Answers

Answer: B

Cost Price of \(1st\) transistor \(= Rs. (\frac{100}{120} \times 840) = Rs. 700.\)

Cost Price of \(2nd\) transistor \(= Rs. (\frac{100}{96} \times 960) = Rs. 1000\)

So, total Cost Price \(= Rs. (700 + 1000) = Rs. 1700.\)

Total Selling Price \(= Rs. (840 +960) = Rs. 1800.\)

\(\therefore\) Gain % \(= (\frac{100}{1700} \times 100)\) % \(= 5\frac{15}{17}\) %

Answer: B

Cost Price of \(56 kg\) rice \(= Rs. (26 \times 20 + 30 \times 36) = Rs. (520 + 1080) = Rs. 1600.\)

Selling Price of \(56kg\) rice \(= Rs. (56 \times 30) = Rs. 1680.\)

\(\therefore\) Gain \(= (\frac{80}{1600} \times 100)\) % \(= 5\) %.

Answer: B

Cost Price of bicycle \(= x\)

Then Cost Price of \(2nd\) bicycle is \(750 - x.\)

Their Selling Price be \(\frac{122}{100} \times x\) and \(\frac{92}{100} \times (750 - x)\)

Given that there is no profit no loss.

\(\frac{122}{100} \times x + \frac{92}{100} \times (750 - x) = 750\)

\(\Rightarrow 122x + 750 \times 92 - 92x = 750 \times 100\)

\(\Rightarrow 122x - 92x = 750 \times 100 - 750 \times 92\)

\(\Rightarrow 30x = 750 \times (100 - 92)\)

\(x = 200.\)

Selling Price of \(1st\) bicycle \(= \frac{122}{100} \times 200 = Rs 244.\)

Answer: D

Let the Cost Price of item \(A\) be \(x\)

Cost Price of item \(B \) is \(x + 200.\)

\(\frac{(\frac{120}{100} \times x)}{(x + 200) \times \frac{70}{100}} = \frac{6}{7} \)

\(\frac{120x}{(x + 200) \times 70} = \frac{6}{7}\)

\(\frac{20x}{10(x + 200)} = 1\)

\(x = Rs 200.\)

Cost Price of item \(B\) is \(200 + 200 = Rs 400.\)

Answer: B

Mango \(= X;\) Grape \(= Y;\) Apple \(= Z;\)

\(2X + 3Y + 4Z= 15 - 1\)

\(3X + 2Y + Z = 10 - 2\)

Adding (1) and (2) \(5X + 5Y + 5Z = 25\)

Clearly, \(X + Y + Z = 5\)

So cost of \(3\) Mangoes, \(3\) Grapes and \(3\) Apples will be \(3X + 3Y + 3Z \) \(i.e, 15\)

Answer: C

Total cost to produced \(1500\) watches \(= (1500 \times 150 + 30000) = Rs. 2,55,000\)

Let he sells \(x\) watches during the season, therefore

Number of watches sold after the season \(= (1500 - x)\)

\(\Rightarrow 250 \times x + (1500 - x) \times 100 = 150x + 150000\)

Now, break - even is achieved if production cost is equal to the selling price.

\(150x + 150000 = 2,55,000\)

\(x = 700\)

Answer: A

MP \(= \frac{120}{(\frac{80}{100})} = 150\)

Now he is selling 16 goods to a dozen(ie 12),

so his loss \(= {\frac{(16-12)}{16}} \times 100 = 25\) %.

Then the actual MP \(\frac{150}{(\frac{75}{100})} = 200\)

Hence, he has marked the MP \(100\) ?ove the CP.

Answer: C

The total amount distributed among 55 officers \(= Rs. 55 \times 1200 = Rs. 6,60,000.\)

Their ratio \(5:3\)

Total profit \(= 6,60,000 + 396000 = Rs 10,56,000.\)

Answer: A

The Cost Price be

\(2120 + 1500 = 3640\)

\(\frac{3640}{2} = 1820.\)

Selling Price \(= \frac{1820 \times 125}{100} = \frac{1820 \times 5}{4}\)

\(= Rs 2275\)

Answer: C

Let Cost Price \(= Rs . 100.\)

Then, Profit \(= Rs. 270,\)

Selling Price \(Rs. 370.\)

New Cost Price \(= 130\)% of \(Rs. 100 = Rs. 130\)

New Selling Price \(= Rs. 370.\)

Profit \(= Rs. (370 - 130) = Rs. 240\)

Required  percentage \(= (\frac{240}{370}) \times 100 = 64.86 = 65\)% (approx)