A cyclone handles \( 1.8 \) m\(^3\)/s of air through an inlet of \( 0.15 \) m\(^2\). The inlet velocity is
Answer: C
Correct answer: 12.0 m/s
Velocity is volumetric flow divided by area:
\[ v = \frac{1.8}{0.15} = 12.0\ \mathrm{m/s} \]
Inlet velocity governs cyclone performance directly, since the centrifugal force separating the dust from the air rises with its square. Too low and fine material escapes with the exhaust; too high and pressure drop and erosion rise steeply. Design velocities for grain dust cyclones typically fall in the range of 12 to 20 m/s, so this machine sits at the gentle end.
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