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Time & Distance Questions and Answers

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111.

The distance between Delhi and Mathura is 110 km. A starts from Delhi at 7 a.m. with a speed of 20 kmph towards Mathura, and B starts from Mathura at 8 a.m. with a speed of 25 kmph towards Delhi. When will they meet?

Answer: B

A has a one-hour head start:

\[ 20 \times 1 = 20 \text{ km covered by 8 a.m.} \]

\[ \text{gap remaining} = 110 - 20 = 90 \text{ km} \]

They approach at \( 20 + 25 = 45 \) kmph:

\[ t = \frac{90}{45} = 2 \text{ hours} \]

So they meet at 10 a.m.

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112.

A train of 24 carriages, each of 60 meters length, when an engine also of 60 meters length is running at a speed of 60 kmph. In what time will the train cross a bridge 1.5 km long?

Answer: B

\[ 1 \text{ kmph} = \frac{5}{18} \text{ m/s} \]

The whole train is the engine plus 24 carriages, each 60 m:

\[ 25 \times 60 = 1500 \text{ m} \]

\[ 60 \text{ kmph} = \frac{50}{3} \text{ m/s} \]

\[ t = \frac{1500 + 1500}{50/3} = \frac{3000 \times 3}{50} = 180 \text{ s} = 3 \text{ minutes} \]

The engine counts as a twenty-fifth 60 m unit, and the bridge's 1.5 km must be converted to 1500 m.

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113.

A motorcyclist goes from Bombay to Pune, a distance of 192 kms at an average of 32 kmph speed. Another man starts from Bombay by car 2 ½ hours after the first, and reaches Pune ½ hour earlier. What is the ratio of the speed of the motorcycle and the car?

Answer: A

\[ t_{\text{motorcycle}} = \frac{192}{32} = 6 \text{ hours} \]

The car starts \( 2\tfrac{1}{2} \) hours later and arrives half an hour earlier:

\[ t_{\text{car}} = 6 - 2.5 - 0.5 = 3 \text{ hours} \]

\[ v_{\text{car}} = \frac{192}{3} = 64 \text{ kmph} \]

\[ 32 : 64 = 1 : 2 \]

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114.

A 600 meter long train crosses a signal post in 40 seconds. How long will it take to cross a 3 kilometer long bridge, at the same speed?

Answer: A

A signal post is a point, so the first crossing gives the speed.

\[ v = \frac{600}{40} = 15 \text{ m/s} \]

\[ t = \frac{600 + 3000}{15} = \frac{3600}{15} = 240 \text{ s} = 4 \text{ minutes} \]

The data are complete, so "data inadequate" is a trap; the 3 km must be converted to 3000 m.

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115.

Two men A and B start from place X walking at 4 ½ kmph and 5 ¾ kmph respectively. How many km apart they are at the end of 3 ½ hours if they are walking in the same direction?

Answer: C

Walking the same way, the gap grows at the difference of their speeds.

\[ 5\tfrac{3}{4} - 4\tfrac{1}{2} = 1.25 \text{ kmph} \]

\[ 1.25 \times 3.5 = 4.375 = 4\tfrac{3}{8} \text{ km} \]

Had they walked in opposite directions the gap would grow at the sum, 10.25 kmph, giving \( 35\tfrac{7}{8} \) km - which is the last option.

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116.

Two passenger trains start at the same hour in the day from two different stations and move towards each other at the rate of 16 kmph and 21 kmph respectively. When they meet, it is found that one train has traveled 60 km more than the other one. The distance between the two stations is?

Answer: B

The 60 km difference comes from the difference in speeds.

\[ 21t - 16t = 60 \quad\Longrightarrow\quad 5t = 60 \quad\Longrightarrow\quad t = 12 \text{ h} \]

They approach at \( 16 + 21 = 37 \) kmph:

\[ d = 37 \times 12 = 444 \text{ km} \]

Checking: 192 km and 252 km, differing by exactly 60.

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117.

How long does a train 110 m long traveling at 60 kmph takes to cross a bridge of 170 m in length?

Answer: D

\[ 1 \text{ kmph} = \frac{5}{18} \text{ m/s} \]

\[ 60 \text{ kmph} = \frac{50}{3} \text{ m/s} \]

\[ t = \frac{110 + 170}{50/3} = \frac{280 \times 3}{50} = 16.8 \text{ sec} \]

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118.

A train sets off at 2 p.m. at the speed of 70 kmph. Another train starts at 3:30 p.m. in the same direction at the rate of 85 kmph. At what time the trains will meet?

Answer: C

The first train has a \( 1\tfrac{1}{2} \) hour head start:

\[ 70 \times 1.5 = 105 \text{ km} \]

The gap closes at \( 85 - 70 = 15 \) kmph:

\[ t = \frac{105}{15} = 7 \text{ hours} \]

\[ 3{:}30 \text{ p.m.} + 7 \text{ h} = 10{:}30 \text{ p.m.} \]

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119.

A train passes a man standing on the platform. If the train is 170 meters long and its speed is 72 kmph, how much time it took in doing so?

Answer: D

\[ 1 \text{ kmph} = \frac{5}{18} \text{ m/s} \]

\[ 72 \text{ kmph} = 20 \text{ m/s} \]

A man is a point, so only the train's own length is covered:

\[ t = \frac{170}{20} = 8.5 = 8\tfrac{1}{2} \text{ sec} \]

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120.

A train 540 meters long is running with a speed of 54 kmph. The time taken by it to cross a tunnel 180 meters long is?

Answer: C

\[ 1 \text{ kmph} = \frac{5}{18} \text{ m/s} \]

\[ 54 \text{ kmph} = 15 \text{ m/s} \]

\[ t = \frac{540 + 180}{15} = \frac{720}{15} = 48 \text{ sec} \]

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