Discussion
A motorcyclist goes from Bombay to Pune, a distance of 192 kms at an average of 32 kmph speed. Another man starts from Bombay by car 2 ½ hours after the first, and reaches Pune ½ hour earlier. What is the ratio of the speed of the motorcycle and the car?
Answer: A
\[ t_{\text{motorcycle}} = \frac{192}{32} = 6 \text{ hours} \]
The car starts \( 2\tfrac{1}{2} \) hours later and arrives half an hour earlier:
\[ t_{\text{car}} = 6 - 2.5 - 0.5 = 3 \text{ hours} \]
\[ v_{\text{car}} = \frac{192}{3} = 64 \text{ kmph} \]
\[ 32 : 64 = 1 : 2 \]
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