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Flow Measurement Devices Questions and Answers

11.

The discharge through a V- notch varies as:
(Where H is the head)

Exam Year(s)

RSMSSB JE - 2025, RSMSSB - 2025,

Answer: C

The discharge through a V-notch varies as \(H^{5/2}\).

For a triangular notch of included angle \(\theta\):

\[ \begin{aligned} Q &= \frac{8}{15} C_d \sqrt{2g} \\ &\quad \times \tan\frac{\theta}{2}\, H^{5/2} \end{aligned} \]

The extra power compared with a rectangular weir comes from the width of the flow growing with the head. \(H^{3/2}\) is the law for a rectangular notch or weir, and \(H^{1/2}\) is the law for an orifice, where velocity alone grows as \(\sqrt{H}\). Discharge proportional to H fits none of these devices.

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12.

A pitot static tube placed in the center of a 200 mm pipe line, has one orifice pointing upstream and the other perpendicular to it. If the pressure difference between the two orifices is 40 mm of water when the discharge through the pipe is 1365 liters/min, then the coefficient of the Pitot tube is:
(Take the mean velocity in the pipe to be 0.83 of the central velocity)

Exam Year(s)

RSMSSB JE - 2025, RSMSSB - 2025,

Answer: A

The coefficient of the Pitot tube is C = 0.984.

First find the mean velocity from the discharge, then the centre velocity:

\[ \begin{aligned} Q &= 1365/60000 = 0.02275\ \text{m}^3/\text{s} \\ A &= \pi (0.1)^2 = 0.03142\ \text{m}^2 \\ V_m &= 0.02275/0.03142 = 0.724\ \text{m/s} \\ V_c &= 0.724/0.83 = 0.872\ \text{m/s} \end{aligned} \]

The Pitot tube gives \(V_c = C\sqrt{2gh}\) with \(h = 0.04\) m of water:

\[ \begin{aligned} \sqrt{2 \times 9.81 \times 0.04} &= 0.886 \\ C &= 0.872/0.886 = 0.984 \end{aligned} \]

Using the mean velocity instead of the centre velocity gives about 0.82, which is not offered; the other options match no step.

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13.

Starting from the first principles, the expression for discharge of a liquid (Q) through a venturimeter is given by:
Where, Q = discharge in m3/s
K = discharge coefficients
C = constant of venturimeter
h = venturi head in meters of a fluid flowing through venturimeter

Exam Year(s)

RSMSSB JE - 2025, RSMSSB - 2025,

Answer: C

The discharge is \(Q = KCh^{1/2}\).

Applying Bernoulli's equation and continuity between the inlet and the throat gives the theoretical discharge:

\[ Q_{th} = \frac{a_1 a_2}{\sqrt{a_1^2 - a_2^2}} \sqrt{2gh} \]

Everything except \(\sqrt{h}\) is fixed for a given meter, so it is grouped as the meter constant C, and the discharge coefficient K allows for losses: \(Q = KC\sqrt{h}\). Discharge must grow as the square root of the head, so the forms with h to the first power, or with roots on K or C, are wrong.

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14.

Match List - I with List - II :

List - IList - II
(a) Venturimeter(I) Pressure measurement
(b) Orifice meter(II) Bend at right angle
(c) Pitot tube(III) Converging diverging section
(d) Manometer(IV) Hole in a plate

Choose the most appropriate answer from the options given below :

Exam Year(s)

RSMSSB JE - 2025, RSMSSB - 2025,

Answer: C

The correct matching is (a)-(III), (b)-(IV), (c)-(II), (d)-(I).

  • Venturimeter: a converging-diverging section; the pressure drop at the throat measures the flow (a-III).
  • Orifice meter: a plate with a hole in it, inserted in the pipe (b-IV).
  • Pitot tube: a tube bent at right angles, its open end facing the flow, to measure velocity (c-II).
  • Manometer: a device for pressure measurement (d-I).

Only one option has the venturimeter against the converging-diverging section and the orifice meter against the hole in a plate; the option (a)-(III), (b)-(II) swaps the orifice meter and the Pitot tube.

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15.

A venturi meter is used for measuring :

Exam Year(s)

RSMSSB JE - 2025, RSMSSB - 2025,

Answer: A

A venturi meter is used for measuring the flow rate.

The venturi meter has a converging section, a throat and a gradually diverging section. The fluid speeds up and its pressure falls at the throat; the pressure difference between the inlet and the throat, read on a manometer, gives the discharge through Bernoulli's and the continuity equations, \(Q = C_{d} A_{1}A_{2}\sqrt{2gh}/\sqrt{A_{1}^{2} - A_{2}^{2}}\).

It does measure a pressure drop, but only as the means of finding the discharge, which is its purpose. Point velocity is measured with a pitot tube, and total head is not what the device is built to give.

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