Discussion
The discharge through a V- notch varies as:
(Where H is the head)
Answer: C
The discharge through a V-notch varies as \(H^{5/2}\).
For a triangular notch of included angle \(\theta\):
\[ \begin{aligned} Q &= \frac{8}{15} C_d \sqrt{2g} \\ &\quad \times \tan\frac{\theta}{2}\, H^{5/2} \end{aligned} \]
The extra power compared with a rectangular weir comes from the width of the flow growing with the head. \(H^{3/2}\) is the law for a rectangular notch or weir, and \(H^{1/2}\) is the law for an orifice, where velocity alone grows as \(\sqrt{H}\). Discharge proportional to H fits none of these devices.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development