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DSB and SSB Modulation Questions and Answers

Answer: B

One tone produces a constant envelope, so the amplifier is never asked to follow a varying level and compression and intermodulation simply do not appear. Two tones give a known two-to-one peak-to-average ratio and a well-defined set of products to measure. A single tone is no more likely to over-drive. Generating two accurate tones is harder rather than easier. And two tones raise the peak-to-average ratio rather than halving the peak power.

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Answer: C

The filter must fall from passband to stopband within twice the message's lowest frequency, a few hundred hertz, and achieving that at a usable centre frequency is what makes crystal, ceramic or mechanical construction necessary. Insertion loss is easily made up with gain. Impedance is a matching matter. Temperature coefficient matters for frequency accuracy but is a far smaller design difficulty than the transition width, which is why the filter method is defined by its filter.

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Answer: D

Vestigial sideband keeps one full sideband and a small part of the other, retaining the low-frequency content that a sharp filter would destroy while saving most of the bandwidth SSB would save. It is emphatically an amplitude scheme rather than an angle one. Its carrier is retained rather than suppressed, so envelope detection works. And it is not single sideband with a pilot, which would be a different compromise addressing the carrier rather than the filter problem.

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Answer: A

Linear class AB operation is markedly less efficient than the class C stages an unmodulated or angle-modulated carrier permits, so an SSB transmitter runs hotter and draws more supply power for a given output. That is the price of putting information in the envelope. Bandwidth is narrower than DSB-SC, not wider. Its receiver uses a product detector rather than a diode. And solid-state linear amplifiers are entirely standard.

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Answer: B

With no transmitted carrier and no symmetry to lock to, an SSB receiver can only set its reinserted carrier from its own dial, so any transmitter frequency error appears directly as an audio pitch shift. Both ends must therefore be accurate. Full-carrier AM is envelope detected and tolerant. DSB-SC provides a symmetric spectrum that a Costas loop can lock to, which relieves the requirement. And vestigial sideband retains a carrier for the receiver to follow.

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Answer: C

Adding back a carrier large enough that the envelope follows the message turns DSB-SC into full-carrier AM, which is exactly what deliberately unbalancing the modulator achieves. Removing a sideband would give SSB instead. A quadrature phase shift is a step in the phasing method of SSB generation. And raising the message amplitude without a carrier present does not create one; it merely scales the sidebands.

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