The d-spacing of a plane (110) of a cubic crystal with lattice parameter a = 5 Å is :
MH SET - 2020, SET Exam - 2020,
Answer: C
The d-spacing of (110) is 3.54 Å.
For a cubic crystal with lattice parameter a, the spacing of the (hkl) planes is
\[ \begin{aligned} d_{hkl} &= \frac{a}{\sqrt{h^{2} + k^{2} + l^{2}}} \\ d_{110} &= \frac{5}{\sqrt{1 + 1 + 0}} = \frac{5}{1.414} = 3.54\ \text{Å} \end{aligned} \]
7.07 Å is what you get by multiplying by \(\sqrt{2}\) instead of dividing. 2.5 Å is a/2, the spacing of (200), and 0.28 is the reciprocal of 3.54, from inverting the formula.
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