Discussion
The d-spacing of a plane (110) of a cubic crystal with lattice parameter a = 5 Å is :
Answer: C
The d-spacing of (110) is 3.54 Å.
For a cubic crystal with lattice parameter a, the spacing of the (hkl) planes is
\[ \begin{aligned} d_{hkl} &= \frac{a}{\sqrt{h^{2} + k^{2} + l^{2}}} \\ d_{110} &= \frac{5}{\sqrt{1 + 1 + 0}} = \frac{5}{1.414} = 3.54\ \text{Å} \end{aligned} \]
7.07 Å is what you get by multiplying by \(\sqrt{2}\) instead of dividing. 2.5 Å is a/2, the spacing of (200), and 0.28 is the reciprocal of 3.54, from inverting the formula.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development