Circular Seating Arrangement Questions and Answers

Answer: C

Q is at the immediate right of S. Seat Q at the bottom of the square, facing the centre. P is second to the right of Q, so P is directly opposite Q. R is at the immediate left of P, which places R on Q's right-hand side, and S takes the remaining seat on Q's left. S, facing the centre from the left side, has Q on its right. So Q is at the immediate right of S. P is opposite Q, so it is neither the immediate right nor the immediate left of Q. Q's immediate left is S, so the statement that Q is at the immediate left of S is the reverse of what is true.

Answer: C

The person sitting 3rd to the right of Ajay is Madhuri. The eight stars sit in a circle facing outwards, so each person's right is the anticlockwise side. Since no two men or two women are adjacent, men and women alternate. Salman and Amitabh sit opposite each other, Madhuri is between Salman and Shahrukh, and Raveena is opposite Madhuri.

Going clockwise as seen from above, one arrangement that fits every clue is Salman, Kareena, Ajay, Raveena, Amitabh, Kajol, Shahrukh, Madhuri. Ajay is the 2nd to the right of Amitabh, Kajol is not next to Ajay, and the genders alternate. From Ajay, the 1st to the right is Kareena, the 2nd is Salman and the 3rd is Madhuri. The mirror image of this seating (with the opposite facing) gives the same name, so Kajol, Raveena and Kareena are the wrong choices.

Answer: D

The person second to the right of E is F. The printed list names E twice and never lists F, though the stem later mentions F, so the sixth friend is F. Facing the centre, a person's right is the anticlockwise neighbour. Put B at seat 0 and number the seats clockwise 0 to 5. D sits opposite B, so D is at 3. F is the immediate right of B, so F is at 5. A is second to the left of C, so A is two seats clockwise of C. Only seats 1, 2 and 4 remain for A, C and E, and only C = 2, A = 4 works, which leaves E at 1. Two seats anticlockwise of E (seat 1) is seat 5, which is F. A, B and D are the people at seats 4, 0 and 3, so none of them is second to E's right.

Answer: C

Q is a neighbor of R and U.

Six people round a table occupy six equally spaced seats. Put P in seat 1. P sits next to S and T, so S and T take seats 2 and 6. Q is diametrically opposite P, in seat 4. That leaves seats 3 and 5 for R and U, which are exactly the two seats beside Q.

The third statement only decides which of R and U takes seat 3 and which seat 5 (with S in seat 2 and T in seat 6, both placements give equal S-R and T-U distances). Either way, R and U fill the two seats next to Q. S and T are next to P, not Q, and P is opposite Q, so the other options are impossible.

Answer: A

Third to the left of V is X.

Number the eight seats 0 to 7 around the table, counting 'to the left' as one direction round the circle. Put T in seat 0.

• Z is third to the left of T: seat 3.
• Z is second to the right of S, so S is two seats to the left of Z: seat 5.
• T's neighbours are Y and V, in seats 1 and 7. U sits between S and Y, so U must be in seat 6 next to S, which puts Y in seat 7 and V in seat 1.
• W and X take seats 2 and 4. Seat 4 is opposite T, and W is not opposite T, so W is in seat 2 and X in seat 4.

Counting three seats to the left of V (seat 1) reaches seat 4, which is X. W is one seat to the left of V, U is three seats to the right of V, and T is V's neighbour on the right, so none of them is third to the left.

Answer: B

The person to the immediate right of B is E.

Only two people face the centre, and both neighbours of G face it, so those two are G's neighbours and everyone else faces outward. Working through the clues fixes one arrangement. Going round the circle in one direction: A, H, F, G, D, E, B, C, with D and F (G's neighbours) facing the centre.

Checks: F is second to the left of D (D faces in); A is second to the left of F (F faces in); one person, C, sits between A and B; C is to A's immediate right (A faces out); neither C nor E sits next to F. B faces outward, so B's right is towards E.

F, C and D are not B's right-hand neighbour in this arrangement; C is B's left-hand neighbour.

Answer: A

David sits between Binoy and Elias.

Number the six seats round the table 1 to 6. Put Atul at seat 1, so Binoy, opposite him, is at seat 4. Atul's two neighbours (seats 2 and 6) must be Elias and Chaaya, because each is said to sit next to Atul.

Chaaya sits between Atul and Firoz, and Firoz sits next to Binoy. So Chaaya is at seat 2 and Firoz at seat 3, beside Binoy at 4. That leaves Elias at seat 6 and David at seat 5, between Elias and Binoy, as the clue about Elias requires.

   Atul(1)

Elias(6)  Chaaya(2)

David(5)  Firoz(3)

   Binoy(4)

Firoz and Chaaya are on the other side of the table, and Binoy cannot sit between himself and Elias.

Answer: B

The sweet two places to the left of Gulab jamun is Rasagulla.

Seat the six sweets round the table in order, counting to the right. Put Halwa in place 1, so Burfi, opposite it, is in place 4. Gulab jamun is immediately to the right of Halwa, in place 2.

That leaves places 3, 5 and 6 for Laddu, Jalebi and Rasagulla. Laddu and Jalebi need exactly one sweet between them, which only places 3 and 5 allow (Burfi sits between them). So Rasagulla is in place 6.

Two places to the left of Gulab jamun (place 2) is place 6: one place left is Halwa, two places left is Rasagulla.

Halwa is only one place to the left, and Laddu and Jalebi sit on the other side of Gulab jamun.

Answer: D

The person third to the right of A is S.

All six face the centre, so for each person 'right' is anticlockwise and 'left' clockwise, seen from above. Number the seats 0 to 5 clockwise and put R at 0.

• H is immediately right of R: seat 5.
• K is second to the left of R: seat 2.
• A is second to the right of E. The only free pair that fits is E at 3 and A at 1, leaving S at 4.

Counting three seats to the right (anticlockwise) from A at 1 gives 0, 5, 4, which is S.

Answer: C

The pairs sitting opposite each other are CD and ts.

Number the seats 1 to 5 from west to east. The girls face north, so a girl's right is east; the boys face south, so a boy's left is east. C is just right of A and A is at an end, so A is in seat 1 and C in seat 2, and t, opposite C, is in seat 2. q is just to the left of s, so q sits one seat east of s, opposite E. B and r are diagonally opposite, at opposite ends of the two rows. If s and q took seats 4 and 5, E would be at seat 5 and B could not be at an end, so s is in seat 3, q and E in seat 4, r in seat 1 and B in seat 5. That leaves p in seat 5 and D in seat 3.

C and D sit side by side in seats 2 and 3, directly facing t and s in the same seats. AC faces rt, not sp, and the pair CD does not face rt.

D also faces s and B faces p, but D and B are not neighbours (E sits between them), and neither are s and p (q sits between them), so 'DB and sp' are not pairs sitting opposite each other in the sense the question uses, of two neighbours facing two neighbours.