Discussion
Six friends, A, B, C, D, E and E, are sitting around a round table facing toward the centre and equidistant from each other. A is sitting second to the left of C. D is sitting opposite to B. F is sitting to the immediate right of B. Who is sitting second to the right of E?
Answer: D
The person second to the right of E is F. The printed list names E twice and never lists F, though the stem later mentions F, so the sixth friend is F. Facing the centre, a person's right is the anticlockwise neighbour. Put B at seat 0 and number the seats clockwise 0 to 5. D sits opposite B, so D is at 3. F is the immediate right of B, so F is at 5. A is second to the left of C, so A is two seats clockwise of C. Only seats 1, 2 and 4 remain for A, C and E, and only C = 2, A = 4 works, which leaves E at 1. Two seats anticlockwise of E (seat 1) is seat 5, which is F. A, B and D are the people at seats 4, 0 and 3, so none of them is second to E's right.
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